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What are the solutions of the equation x^2 + 14x = -130? A. 2, –16 B. 10, –13 C. –2, 16 D. No Solution

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Can you show me how to solve for the answers?
\[x ^{2} + 14x = -130\]
it's good to know alternate and quick methods sometimes. Substitute each pair values to see if they = -130

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Other answers:

add 130 to both sides. Now use discriminant b^2 - 4ac, for ax^2 +bx + c. Remember that when this is less than 0, there are no real solutions. This is the case for this quadratic, since 14^2< 4*130

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