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MarcLeclair
 one year ago
A doubleslit pattern is observed on a screen 3m from the slits. Given that the light is incident normally and has a wavelength of 390nm, what is the minimum slit seperation for a point 3.8mm from the centre of the middle bright fringe to be
A) A maximum
b) a minimum
MarcLeclair
 one year ago
A doubleslit pattern is observed on a screen 3m from the slits. Given that the light is incident normally and has a wavelength of 390nm, what is the minimum slit seperation for a point 3.8mm from the centre of the middle bright fringe to be A) A maximum b) a minimum

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MuH4hA
 one year ago
Best ResponseYou've already chosen the best response.0What have you got so far?

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0I feel like I'm missing data. I can't use \[dsin \theta= x _{1}x2\]

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0the question doesn't even specify if they are in phase or out of phase :/

MuH4hA
 one year ago
Best ResponseYou've already chosen the best response.0Who are 'they' ? And no, you are not missing data, you just need to think a little  I'm sure, you can do it..

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0the two light rays... if they are out of phase the equation will change.

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0Its okay I figured it out :) thanks thoug

MuH4hA
 one year ago
Best ResponseYou've already chosen the best response.0Well, I'd claim the problem implies, there is only one light source behind the doubleslit plate. Also, if different areas of the source are emitting with different phases  independent from one another  which is the case for most sources, the phases of the resulting waves in slit 1 and slit 2 will vary (statistically). However, this will _not_ mess with the intensity of the wave at a given point on the screen, given the variations are synchronous, cause the phasedifference of the outgoing waves (Huygens principle) from S1 and S2 is timeinvariant. In this case the two slits are forming two coherent lightsources that will show a timeindependent interferencepattern on the screen. (Sry, english is a 2nd language  hope that makes sense...)

MuH4hA
 one year ago
Best ResponseYou've already chosen the best response.0You did? Congratulations ;)
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