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appleduardo

  • 3 years ago

whats the integral for dx/x^3 ?

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  1. wio
    • 3 years ago
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    The integral? Do you mean the anti-derivative? Remember that \(1/x^3 = x^{-3}\) and \[ \int x^n dx = \frac{x^{n+1}}{n+1}+C,\quad n\ne-1 \]

  2. appleduardo
    • 3 years ago
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    so i'll get: x^-3 and then: \[\frac{ x ^{-2} }{ -2 } \] is that ok?

  3. wio
    • 3 years ago
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    That is okay, but so is \[ \frac{x^{-2}}{-2}+1 \]as well. So you're excluding a possible anti-derivative out. That's mean you know.

  4. wio
    • 3 years ago
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    Why won't you give \[ \frac{x^{-2}}{-2}-60 \]a chance either? \(-60\) has a family to feed as well.

  5. wio
    • 3 years ago
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    @appleduardo ?

  6. appleduardo
    • 3 years ago
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    u mean that i forgot to write aside " + c " :$

  7. wio
    • 3 years ago
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    Yeah.

  8. appleduardo
    • 3 years ago
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    :p thank you ! :d

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