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CharityDanielle Group Title

hoose the correct description of the graph of the compound inequality x - 1 < or = to 9 or 2x > or = to 24 A number line with an open circle on 10, shading to the left, and an open circle on 12, shading to the right. A number line with an open circle on 10, an open circle on 12, and shading in between. A number line with a closed circle on 10, a closed circle on 12, and shading in between. A number line with a closed circle on 10, shading to the left, and a closed circle on 12, shading to the right

  • one year ago
  • one year ago

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  1. CharityDanielle Group Title
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    @dmezzullo sorry for taggiin you soo much..i know you must hate me right now ):

    • one year ago
  2. dmezzullo Group Title
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    Its ok idk this one

    • one year ago
  3. CharityDanielle Group Title
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    poo

    • one year ago
  4. satellite73 Group Title
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    \[x-1\leq 9\iff x\leq 10\]

    • one year ago
  5. CharityDanielle Group Title
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    huh????????????

    • one year ago
  6. satellite73 Group Title
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    \[2x\geq 24\iff x\geq 12\]

    • one year ago
  7. CharityDanielle Group Title
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    im confsed!!

    • one year ago
  8. satellite73 Group Title
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    before you can answer the question, you have to solve each inequality for \(x\) that is the first step

    • one year ago
  9. satellite73 Group Title
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    the first inequality is \(x-1\leq 9\) to solve this for \(x\) add 1 to both sides, which gives you \[x\leq 10\]

    • one year ago
  10. satellite73 Group Title
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    to solve \(2x\geq 24\) divide both sides by 2 and get \(x\geq 12\)

    • one year ago
  11. satellite73 Group Title
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    this tells you \(x\leq 10\) OR \(x\geq 12\)

    • one year ago
  12. satellite73 Group Title
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    |dw:1364999820534:dw|

    • one year ago
  13. satellite73 Group Title
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    both circles are closed because you have \(\leq\) and \(\geq\) instead of \(<\) and \(>\)

    • one year ago
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