hoose the correct description of the graph of the compound inequality x - 1 < or = to 9 or 2x > or = to 24 A number line with an open circle on 10, shading to the left, and an open circle on 12, shading to the right. A number line with an open circle on 10, an open circle on 12, and shading in between. A number line with a closed circle on 10, a closed circle on 12, and shading in between. A number line with a closed circle on 10, shading to the left, and a closed circle on 12, shading to the right

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hoose the correct description of the graph of the compound inequality x - 1 < or = to 9 or 2x > or = to 24 A number line with an open circle on 10, shading to the left, and an open circle on 12, shading to the right. A number line with an open circle on 10, an open circle on 12, and shading in between. A number line with a closed circle on 10, a closed circle on 12, and shading in between. A number line with a closed circle on 10, shading to the left, and a closed circle on 12, shading to the right

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@dmezzullo sorry for taggiin you soo much..i know you must hate me right now ):
Its ok idk this one
poo

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\[x-1\leq 9\iff x\leq 10\]
huh????????????
\[2x\geq 24\iff x\geq 12\]
im confsed!!
before you can answer the question, you have to solve each inequality for \(x\) that is the first step
the first inequality is \(x-1\leq 9\) to solve this for \(x\) add 1 to both sides, which gives you \[x\leq 10\]
to solve \(2x\geq 24\) divide both sides by 2 and get \(x\geq 12\)
this tells you \(x\leq 10\) OR \(x\geq 12\)
|dw:1364999820534:dw|
both circles are closed because you have \(\leq\) and \(\geq\) instead of \(<\) and \(>\)

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