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Hope99
Work = Zero
\[W = \int\limits_{a}^{b} F(x)d(x)\] Is a closed path is always zero why is that?
Well work done by gravity that is...
@satellite73 @ParthKohli @Callisto @mathslover @Mashy
I can imagine that gravity does no work because the start & endpoint is the same. |dw:1365011587034:dw|
Um. The distance did not change I guess, so the work = F x 0 = 0?
|dw:1365011417026:dw|
only by conservative forces.. . :)
and independent of the path followed.