anonymous
  • anonymous
solve for x: sqrt x^2-x-5=5 A. -5 B. -6 C. 6 D. -5, 6
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
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cwrw238
  • cwrw238
your question isa bit confusing do you mean square root oh ok
phi
  • phi
what do you get if you square both sides of the equation ?

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anonymous
  • anonymous
not sure..
phi
  • phi
how about the right side of the = sign ? what is 5*5 ?
anonymous
  • anonymous
25
phi
  • phi
on the left use the rule that a sqrt times itself makes the square root "go away" in other words, sqrt(x) * sqrt(x) is x no matter how complicated x is.
anonymous
  • anonymous
-6
phi
  • phi
All we want is the left side squared. here are some examples sq rt(1+2+3)* sq rt (1+2+3) = 1+2+3 or sq rt(x^2 * 30y)* sq rt (x^2*30y) = x^2*30y what is sq rt (x^2-x-5) * sq rt (x^2-x-5) ?
phi
  • phi
do you need more examples of what happens when you square a square root ?
anonymous
  • anonymous
no:)
phi
  • phi
in that case what is sq rt (x^2-x-5) * sq rt (x^2-x-5) ?
anonymous
  • anonymous
-5,6
phi
  • phi
I have not solved this, so I don't know off hand. You can learn to solve it or you can try substituting in possible answers and see if they work.

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