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katlin95

  • one year ago

solve for x: sqrt x^2-x-5=5 A. -5 B. -6 C. 6 D. -5, 6

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  1. katlin95
    • one year ago
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    |dw:1365027513803:dw|

  2. cwrw238
    • one year ago
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    your question isa bit confusing do you mean square root oh ok

  3. phi
    • one year ago
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    what do you get if you square both sides of the equation ?

  4. katlin95
    • one year ago
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    not sure..

  5. phi
    • one year ago
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    how about the right side of the = sign ? what is 5*5 ?

  6. katlin95
    • one year ago
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    25

  7. phi
    • one year ago
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    on the left use the rule that a sqrt times itself makes the square root "go away" in other words, sqrt(x) * sqrt(x) is x no matter how complicated x is.

  8. katlin95
    • one year ago
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    -6

  9. phi
    • one year ago
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    All we want is the left side squared. here are some examples sq rt(1+2+3)* sq rt (1+2+3) = 1+2+3 or sq rt(x^2 * 30y)* sq rt (x^2*30y) = x^2*30y what is sq rt (x^2-x-5) * sq rt (x^2-x-5) ?

  10. phi
    • one year ago
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    do you need more examples of what happens when you square a square root ?

  11. katlin95
    • one year ago
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    no:)

  12. phi
    • one year ago
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    in that case what is sq rt (x^2-x-5) * sq rt (x^2-x-5) ?

  13. katlin95
    • one year ago
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    -5,6

  14. phi
    • one year ago
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    I have not solved this, so I don't know off hand. You can learn to solve it or you can try substituting in possible answers and see if they work.

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