At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

\(\sqrt{-3}=\sqrt{3}i\)

i know this is with i agai

so
\[-\sqrt{3}\times \sqrt{3}i=-3i\]

ohh so anything with a negative is and imaginary number right

if you have a negative number inside the radical, then it comes outside as \(i\)

yeah because a negative isnt possible in square root

for example \(\sqrt{-25}=\sqrt{25}i=5i\) and
\[\sqrt{-3}=\sqrt{3}i\]

i have a few more question like this can i show you and can you tell me if im doing it right?

√-25√-9
its going to be 5i 3i right?

yes, that would be the first step

the second step would be to actually multiply and get
\[5i\times 3i=15i^2=15\times (-1)=-15\]

the i goes away?

yes, because \(i=\sqrt{-1}\) and so \(i^2=-1\)

thanks for helping me out im stuck with all this and guys are the best :D