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nisa

  • 2 years ago

-√3(√-3) help me pleasee

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  1. satellite73
    • 2 years ago
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    \(\sqrt{-3}=\sqrt{3}i\)

  2. nisa
    • 2 years ago
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    i know this is with i agai

  3. satellite73
    • 2 years ago
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    so \[-\sqrt{3}\times \sqrt{3}i=-3i\]

  4. nisa
    • 2 years ago
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    ohh so anything with a negative is and imaginary number right

  5. satellite73
    • 2 years ago
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    if you have a negative number inside the radical, then it comes outside as \(i\)

  6. nisa
    • 2 years ago
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    yeah because a negative isnt possible in square root

  7. satellite73
    • 2 years ago
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    for example \(\sqrt{-25}=\sqrt{25}i=5i\) and \[\sqrt{-3}=\sqrt{3}i\]

  8. nisa
    • 2 years ago
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    i have a few more question like this can i show you and can you tell me if im doing it right?

  9. nisa
    • 2 years ago
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    √-25√-9 its going to be 5i 3i right?

  10. satellite73
    • 2 years ago
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    yes, that would be the first step

  11. satellite73
    • 2 years ago
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    the second step would be to actually multiply and get \[5i\times 3i=15i^2=15\times (-1)=-15\]

  12. nisa
    • 2 years ago
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    the i goes away?

  13. satellite73
    • 2 years ago
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    yes, because \(i=\sqrt{-1}\) and so \(i^2=-1\)

  14. nisa
    • 2 years ago
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    oh that makes sense and im sorry i just have two more if u could please check them as well (6i)2 which would be 36i right but if i multiplied 36 by -1 then i get -36 then theres (2+3)(2-3i) im not sure about this one like is it going to be like 5*2-3(-1) ?

  15. nisa
    • 2 years ago
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    thanks for helping me out im stuck with all this and guys are the best :D

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