## naatp Group Title The quantity of a charge Q that passes through a surface at time t (seconds), is given by Q=t^3 -2t^2 +6t +2. The current is defined as the rate of change of the charges with respect to t. Find the current when t=2 one year ago one year ago

$i(t)=\frac{ dq }{dt }=3t^2-4t+6$ $i(2)=3(2)^2-4(2)+6=10A$

2. naatp

Apparently the answer is $\frac{ 3 }{ 10\Pi }$ cm/s