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Envii

  • one year ago

1/2 + x/6 = 18/x

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  1. Lynncake
    • one year ago
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    Get the common denominator, and cross multiply...\[\frac{ 1 }{ 2 }+\frac{ x }{ 6 }=\frac{ 18 }{ x } \rightarrow \frac{ 3+x }{ 6 }=\frac{ 18 }{ x }\]\[x(3+x)=6(18) \rightarrow 3x+x^2-108=0 \rightarrow x^2+3x-108=0\]\[(x+12)(x-9)=0\]From here we got two values of x...\[x+12=0 \rightarrow x=-12\]\[x-9=0 \rightarrow x=9\]

  2. Envii
    • one year ago
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    The book says no solution. Does that have no solution?

  3. Lynncake
    • one year ago
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    What's the question? Do they ask for the values of x?

  4. Envii
    • one year ago
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    Oh, I see now. Thank you so much. :)

  5. Lynncake
    • one year ago
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    Ohhhh ok, good luck

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