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LynncakeBest ResponseYou've already chosen the best response.2
Get the common denominator, and cross multiply...\[\frac{ 1 }{ 2 }+\frac{ x }{ 6 }=\frac{ 18 }{ x } \rightarrow \frac{ 3+x }{ 6 }=\frac{ 18 }{ x }\]\[x(3+x)=6(18) \rightarrow 3x+x^2108=0 \rightarrow x^2+3x108=0\]\[(x+12)(x9)=0\]From here we got two values of x...\[x+12=0 \rightarrow x=12\]\[x9=0 \rightarrow x=9\]
 one year ago

EnviiBest ResponseYou've already chosen the best response.0
The book says no solution. Does that have no solution?
 one year ago

LynncakeBest ResponseYou've already chosen the best response.2
What's the question? Do they ask for the values of x?
 one year ago

EnviiBest ResponseYou've already chosen the best response.0
Oh, I see now. Thank you so much. :)
 one year ago
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