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Lynncake
 one year ago
Best ResponseYou've already chosen the best response.2Get the common denominator, and cross multiply...\[\frac{ 1 }{ 2 }+\frac{ x }{ 6 }=\frac{ 18 }{ x } \rightarrow \frac{ 3+x }{ 6 }=\frac{ 18 }{ x }\]\[x(3+x)=6(18) \rightarrow 3x+x^2108=0 \rightarrow x^2+3x108=0\]\[(x+12)(x9)=0\]From here we got two values of x...\[x+12=0 \rightarrow x=12\]\[x9=0 \rightarrow x=9\]

Envii
 one year ago
Best ResponseYou've already chosen the best response.0The book says no solution. Does that have no solution?

Lynncake
 one year ago
Best ResponseYou've already chosen the best response.2What's the question? Do they ask for the values of x?

Envii
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I see now. Thank you so much. :)
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