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anewbie

  • 3 years ago

evaluate limx->3 (sqrt{x^{2}+7}-16)/x^{2}-3x

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  1. anewbie
    • 3 years ago
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    \[\lim_{x \rightarrow 3} (\sqrt{x^{2}+7}-16)/ x^{2}-3x\]

  2. hartnn
    • 3 years ago
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    please verify the question again ?

  3. hartnn
    • 3 years ago
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    because that limit does not exist. if thats correct, then you need to find left hand limit and right hand limit separately.

  4. anewbie
    • 3 years ago
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    the question is just this. i did does not exist but the answer is 1/10 :/

  5. hartnn
    • 3 years ago
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    umm..then there is something wrong with the question, what you have posted, the limit DNE. http://www.wolframalpha.com/input/?i=lim++x-%3E3++%28sqrt%7Bx%5E2%2B7%7D-16%29%2F%28x%5E2-3x%29

  6. anewbie
    • 3 years ago
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    i think the answer key is wrong :/ . thank you so much :))

  7. hartnn
    • 3 years ago
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    hmm...ok, welcome ^_^

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