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anonymous
 3 years ago
evaluate limx>3 (sqrt{x^{2}+7}16)/x^{2}3x
anonymous
 3 years ago
evaluate limx>3 (sqrt{x^{2}+7}16)/x^{2}3x

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 3} (\sqrt{x^{2}+7}16)/ x^{2}3x\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1please verify the question again ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1because that limit does not exist. if thats correct, then you need to find left hand limit and right hand limit separately.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the question is just this. i did does not exist but the answer is 1/10 :/

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1umm..then there is something wrong with the question, what you have posted, the limit DNE. http://www.wolframalpha.com/input/?i=lim++x%3E3++%28sqrt%7Bx%5E2%2B7%7D16%29%2F%28x%5E23x%29

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think the answer key is wrong :/ . thank you so much :))
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