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Find the inverse of the function f(x)=x^{2}8x+4, where <4. State its domain.
 one year ago
 one year ago
Find the inverse of the function f(x)=x^{2}8x+4, where <4. State its domain.
 one year ago
 one year ago

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hartnnBest ResponseYou've already chosen the best response.1
can you complete the square ? know how to ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(f(x)=x^28x+4= (x...)^2...\)
 one year ago

anewbieBest ResponseYou've already chosen the best response.0
so the answer is inversef(x)=4+sqrt{x+12} . domain is x bigger or equal 12 ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
to be more precise, \(f^{1}(x)=4\pm \sqrt{x+12} \) the domain \(x \ge 12 \) is correct.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
wait, its given that x<4
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so, it'll be only \(f^{1}(x)=4  \sqrt{x+12}\) with same domain.
 one year ago

anewbieBest ResponseYou've already chosen the best response.0
how can we understand that it is minus when x<4 ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
4+ anything means >4 4 anything means <4
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
does that clear it up ? or you have different doubt altogether ? :P
 one year ago

anewbieBest ResponseYou've already chosen the best response.0
a little bit :D because it tells about x but we take the function <4 :/
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
oh, .... domain of f(x) means range of its inverse function \(f^{1}(x)\) here, x<4 is domain of f(x), so range of \(f^{1}(x)\) is x<4 , means \(f^{1}(x)\) has least value of 4, so we discard 4+sqrt {x+12} because that will be >4
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
***range of \(f^{1}(x)\) is \(f^{1}(x)\)<4
 one year ago

anewbieBest ResponseYou've already chosen the best response.0
oh. okey. thank youu :)
 one year ago
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