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anything else given for alpha and beta ? or you need k in terms of alpha and beta ?

Hint:
\((x-\alpha)(x-\beta)=x^2+7x+K\)

question has not sufficient data

it has

\(\alpha + \beta = -7\) and \(\alpha \times \beta = k\)

\((x-\alpha)(x-\beta)=x^2-(\alpha+\beta)x+\alpha\beta=x^2+7x+K\)\)
can you finish this

still, you'll not get a value for k, you'll be able to express k in terms of either alpha or beta.

yes.

good enough

I am trying to say something but checking my method first. It seems somewhat different .

2 equations 3 unknowns.....

I don't see why it is better or worse... It is exactly same amount of info

agreed @mathslover

Thank you Hartnn .