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 one year ago
What is the vertex of the graph of y = –4(x + 2)2 + 5?
(2, 5)
(–2, 5)
(5, –2)
(5, 2)
Solve. 5x2 – 20 = 0
x = 5 and x = 4
x = 4 and x = 2
x = –5 and x = 20
x = 2 and x = –2
I think the first one is A and the second one is C
 one year ago
What is the vertex of the graph of y = –4(x + 2)2 + 5? (2, 5) (–2, 5) (5, –2) (5, 2) Solve. 5x2 – 20 = 0 x = 5 and x = 4 x = 4 and x = 2 x = –5 and x = 20 x = 2 and x = –2 I think the first one is A and the second one is C

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AriPotta
 one year ago
Best ResponseYou've already chosen the best response.0the vertex is (h, k) isn't it? so the vertex should be (2, 5)

phi
 one year ago
Best ResponseYou've already chosen the best response.0look at this http://www.mathwarehouse.com/geometry/parabola/standardandvertexform.php can you figure it out ?

AriPotta
 one year ago
Best ResponseYou've already chosen the best response.05x^2 – 20 = 0 5x^2 = 20 x^2 = 4 sqrt(x^2) = +/ sqrt(4) x = +/ 2

AriPotta
 one year ago
Best ResponseYou've already chosen the best response.0so the second one is d

AriPotta
 one year ago
Best ResponseYou've already chosen the best response.0does that make sense?

miah
 one year ago
Best ResponseYou've already chosen the best response.0what about the first one ?

AriPotta
 one year ago
Best ResponseYou've already chosen the best response.0look at my first post
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