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anonymous
 3 years ago
What is the vertex of the graph of y = –4(x + 2)2 + 5?
(2, 5)
(–2, 5)
(5, –2)
(5, 2)
Solve. 5x2 – 20 = 0
x = 5 and x = 4
x = 4 and x = 2
x = –5 and x = 20
x = 2 and x = –2
I think the first one is A and the second one is C
anonymous
 3 years ago
What is the vertex of the graph of y = –4(x + 2)2 + 5? (2, 5) (–2, 5) (5, –2) (5, 2) Solve. 5x2 – 20 = 0 x = 5 and x = 4 x = 4 and x = 2 x = –5 and x = 20 x = 2 and x = –2 I think the first one is A and the second one is C

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the vertex is (h, k) isn't it? so the vertex should be (2, 5)

phi
 3 years ago
Best ResponseYou've already chosen the best response.0look at this http://www.mathwarehouse.com/geometry/parabola/standardandvertexform.php can you figure it out ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.05x^2 – 20 = 0 5x^2 = 20 x^2 = 4 sqrt(x^2) = +/ sqrt(4) x = +/ 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so the second one is d

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does that make sense?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what about the first one ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0look at my first post
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