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miah
Group Title
What is the vertex of the graph of y = –4(x + 2)2 + 5?
(2, 5)
(–2, 5)
(5, –2)
(5, 2)
Solve. 5x2 – 20 = 0
x = 5 and x = 4
x = 4 and x = 2
x = –5 and x = 20
x = 2 and x = –2
I think the first one is A and the second one is C
 one year ago
 one year ago
miah Group Title
What is the vertex of the graph of y = –4(x + 2)2 + 5? (2, 5) (–2, 5) (5, –2) (5, 2) Solve. 5x2 – 20 = 0 x = 5 and x = 4 x = 4 and x = 2 x = –5 and x = 20 x = 2 and x = –2 I think the first one is A and the second one is C
 one year ago
 one year ago

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AriPotta Group TitleBest ResponseYou've already chosen the best response.0
the vertex is (h, k) isn't it? so the vertex should be (2, 5)
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
look at this http://www.mathwarehouse.com/geometry/parabola/standardandvertexform.php can you figure it out ?
 one year ago

AriPotta Group TitleBest ResponseYou've already chosen the best response.0
5x^2 – 20 = 0 5x^2 = 20 x^2 = 4 sqrt(x^2) = +/ sqrt(4) x = +/ 2
 one year ago

AriPotta Group TitleBest ResponseYou've already chosen the best response.0
so the second one is d
 one year ago

AriPotta Group TitleBest ResponseYou've already chosen the best response.0
does that make sense?
 one year ago

miah Group TitleBest ResponseYou've already chosen the best response.0
what about the first one ?
 one year ago

AriPotta Group TitleBest ResponseYou've already chosen the best response.0
look at my first post
 one year ago
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