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DLS

  • 2 years ago

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  1. DLS
    • 2 years ago
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    \[\LARGE \log_2[\log_3(\log_4x)]\]

  2. ParthKohli
    • 2 years ago
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    The domain of \(\log_4 x\) is _ ^_^?

  3. DLS
    • 2 years ago
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    How do we proceed? \[\log_4x>0 ~or \log_3(\log_4x)>0?\]

  4. DLS
    • 2 years ago
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    @ParthKohli do methodwise :|

  5. ParthKohli
    • 2 years ago
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    Let \(\log_3 (\log_4(x)) = a\). You have \(\log _2 (a)\). The domain of that is...?

  6. AravindG
    • 2 years ago
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    use the domain of log in each case ..making note of what is the base,and values possible for each log function

  7. DLS
    • 2 years ago
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    @ParthKohli idk =)

  8. ParthKohli
    • 2 years ago
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    Remember that in the case of logs, the domain is \(a > 0\).

  9. DLS
    • 2 years ago
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    oh yeah i know that :O

  10. DLS
    • 2 years ago
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    so?

  11. ParthKohli
    • 2 years ago
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    So that is the answer to your question!

  12. DLS
    • 2 years ago
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    NO :/

  13. ParthKohli
    • 2 years ago
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    You should also remember that \(\log(x) > 0\) so it is needless to say that \(a > 0\).

  14. DLS
    • 2 years ago
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    answer nahi hai wo :/

  15. ParthKohli
    • 2 years ago
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    Of course that is the answer to your question.\[\{ x \in \mathbb R : x > 0\}\]

  16. DLS
    • 2 years ago
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    arre nahi hai bc :/

  17. ParthKohli
    • 2 years ago
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    lol

  18. shubhamsrg
    • 2 years ago
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    log2(log3(log4x)) for log2 ( ) to be defined, log3(log4x) >0 that'll mean log4x >1 , hence x>4 ^_^

  19. ParthKohli
    • 2 years ago
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    Just kidding.\[x > 4\]

  20. DLS
    • 2 years ago
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    winner

  21. ParthKohli
    • 2 years ago
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    Arrey yeh Shubham jeet gaye!

  22. shubhamsrg
    • 2 years ago
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    :')

  23. DLS
    • 2 years ago
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    log3(log4x) >0 that'll mean log4x >1 , hence x>4 ??

  24. shubhamsrg
    • 2 years ago
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    yes, sahi kaha :P

  25. DLS
    • 2 years ago
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    kya matlab

  26. ParthKohli
    • 2 years ago
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    Main toh bhool hi gayi thee ki bases bhi hain. lolol

  27. shubhamsrg
    • 2 years ago
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    ye to clear hai ki log3(log4x) > 0 hoga. log 1 = 0, kisi bhi base pe (except 1) hence log4x > 1 hona chaiye h a i n a ?

  28. DLS
    • 2 years ago
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    logs padade bc :/

  29. ParthKohli
    • 2 years ago
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    \[\log_a b = \dfrac{\log b}{\log a}\]

  30. DLS
    • 2 years ago
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    so much win by writing that

  31. DLS
    • 2 years ago
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    http://www.dotallyrad.com/wp-content/uploads/2012/09/1912-so-much-win_inline.jpg

  32. ParthKohli
    • 2 years ago
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    8-)

  33. ParthKohli
    • 2 years ago
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    So much sarcasm! ^_^

  34. DLS
    • 2 years ago
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    no one failed to make me understand till now :3

  35. DLS
    • 2 years ago
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    i mean everyone failed lol

  36. shubhamsrg
    • 2 years ago
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    only one man can save they day he is right here, looking at the question, in silence! is this silence before the storm ? my dear friend, we will know soon, we all know who that person is! comeon @yrelhan4 :')

  37. DLS
    • 2 years ago
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    arre yaar tum log quality answers do :/

  38. ParthKohli
    • 2 years ago
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    :-)

  39. shubhamsrg
    • 2 years ago
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    chala gay :P

  40. shubhamsrg
    • 2 years ago
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    gaya* :|

  41. DLS
    • 2 years ago
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    oh gawd i have to waste another hour on this -_- just one dam question

  42. DLS
    • 2 years ago
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    lol lololol @yrelhan4 jhand

  43. ParthKohli
    • 2 years ago
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    Sorry guys I have IIT JEE at 3 am gotta go

  44. DLS
    • 2 years ago
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    \[\LARGE \log_3{(\log_4x)}>0\]

  45. DLS
    • 2 years ago
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    what next

  46. shubhamsrg
    • 2 years ago
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    abe yaar, sachin ponting dono out :/

  47. ParthKohli
    • 2 years ago
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    Haan yaar, Dinesh hai :-]

  48. DLS
    • 2 years ago
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    @yrelhan4 please

  49. shubhamsrg
    • 2 years ago
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    10 overs 95 runs, banega? :/

  50. ParthKohli
    • 2 years ago
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    Nahi banega!

  51. ParthKohli
    • 2 years ago
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    Gayle hai na banda! 8-)

  52. DLS
    • 2 years ago
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    f u c k y o u g u y s :/ just answer it

  53. yrelhan4
    • 2 years ago
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    Meri besti kregi to mai nhi btaunga aata bhi hoga to. :/

  54. yrelhan4
    • 2 years ago
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    krego*

  55. shubhamsrg
    • 2 years ago
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    sharma jita dega mujhe intuition aa raha hai :)

  56. DLS
    • 2 years ago
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    merse kya dushmani hai yaar BATADO PLEASE

  57. ParthKohli
    • 2 years ago
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    \[\log_3 (\log_4 x) > 0\]Dono sides ka exponentiation karo!

  58. DLS
    • 2 years ago
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    kaise karte hai hai !

  59. shubhamsrg
    • 2 years ago
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    main kabhi tumhari bezzati nahi kRERta @yrelhan4 , sach to sach hota hai :/

  60. shubhamsrg
    • 2 years ago
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    kregta*

  61. DLS
    • 2 years ago
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    STOP IT :/

  62. shubhamsrg
    • 2 years ago
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    hmm, log3(log4x)=0 hai find x ?

  63. DLS
    • 2 years ago
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    wahi puch r aha hoon kaise

  64. ParthKohli
    • 2 years ago
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    Yeah, minimum value^

  65. ParthKohli
    • 2 years ago
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    log ko clear karo

  66. shubhamsrg
    • 2 years ago
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    log(base 3) 1 = 0?

  67. DLS
    • 2 years ago
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    log nahi ata :P

  68. shubhamsrg
    • 2 years ago
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    "0" nahi bolna tha mujhe -_-

  69. ParthKohli
    • 2 years ago
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    \[1 = \log_4 (x)\]^_^

  70. yrelhan4
    • 2 years ago
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    log nhi aata to kya krega. :/

  71. DLS
    • 2 years ago
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    batao to dhang se :/

  72. ParthKohli
    • 2 years ago
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    \[x = 0\]^_^

  73. 50_cent
    • 2 years ago
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    nice job

  74. ParthKohli
    • 2 years ago
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    But!

  75. DLS
    • 2 years ago
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    \[\LARGE 3^{\log_3(\log_4x)}>3^0\]

  76. DLS
    • 2 years ago
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    explain how did we get this:\

  77. ParthKohli
    • 2 years ago
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    Dono sides mein 3 ki power ko kar diya hai.\[a = b \implies 3^a = 3^b\]

  78. shubhamsrg
    • 2 years ago
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    a>b>=0, to x^a > x^b hai na?

  79. DLS
    • 2 years ago
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    3 se kyn kiya?

  80. ParthKohli
    • 2 years ago
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    Because woh \(\log_3\) ka ulta hai!

  81. shubhamsrg
    • 2 years ago
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    yaar ye log itne gande run rate se khel rahe hain! -_-

  82. DLS
    • 2 years ago
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    3 raise to the power log3?

  83. yrelhan4
    • 2 years ago
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    abbe answer de to diya usne? x>4 galat hai? :O

  84. ParthKohli
    • 2 years ago
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    \[2x = 3\]\[\implies x = \dfrac{3}{2}\]2 se divide kyun kiya? Arrey bhai, 2 se multiply karne ka ulta 2 se divide karna honda hai

  85. ParthKohli
    • 2 years ago
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    \[3^{\log_3 a} = a\]

  86. DLS
    • 2 years ago
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    sahi hai par dafuq :/

  87. DLS
    • 2 years ago
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    haan bus wahi sunna tha :P

  88. DLS
    • 2 years ago
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    someone teach me logs someday,ill pay $5

  89. ParthKohli
    • 2 years ago
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    Iske liye itna tang kar rakha tha -_-

  90. ParthKohli
    • 2 years ago
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    5 theoretical dollars?! Manzoor hai!

  91. DLS
    • 2 years ago
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    yesh! Paypal

  92. yrelhan4
    • 2 years ago
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    Ok bye.

  93. ParthKohli
    • 2 years ago
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    Bhaiya, ab logs ko aap intuition se dekho

  94. yrelhan4
    • 2 years ago
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    @shubhamsrg Medal?

  95. ParthKohli
    • 2 years ago
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    ^ Demanding ladke! :-P

  96. shubhamsrg
    • 2 years ago
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    pehle bhi bataya hai maangne pe nahi deta :/

  97. DLS
    • 2 years ago
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    lol

  98. DLS
    • 2 years ago
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    padado ? C:

  99. ParthKohli
    • 2 years ago
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    Dekho, \(\log_a b\) gets you a value which you raise to \(a\) to get \(b\).

  100. DLS
    • 2 years ago
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    thanks,closed

  101. ParthKohli
    • 2 years ago
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    Bas yahi hote hain logs

  102. DLS
    • 2 years ago
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    :"D

  103. ParthKohli
    • 2 years ago
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    Trigonometry bhi kya hoti hai? Bas 3 ratio hote hain aur kya!

  104. DLS
    • 2 years ago
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    Calculus,dy/dx

  105. yrelhan4
    • 2 years ago
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    Fir se batane ke liye medal @shubhamsrg :P

  106. ParthKohli
    • 2 years ago
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    Haan, aur kya, bas rate of change hi hota hai integral aur differential calculus!

  107. DLS
    • 2 years ago
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    2+2=maths

  108. ParthKohli
    • 2 years ago
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    Aur kya! Maths is too simple! Bas ye pata karo ki \(1 + 1 = 2\) aur baaki derive kar lo!

  109. DLS
    • 2 years ago
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    yaar koi division sikhado

  110. DLS
    • 2 years ago
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    63/68 karke dikhado drawing se @yrelhan4 @shubhamsrg @ParthKohli

  111. ParthKohli
    • 2 years ago
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    \[1 + 1 + 1 + 1\]ko\[1 + 1\]parts mein divide karo

  112. DLS
    • 2 years ago
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    mai seriously bhool gaya kaise karte hai :/

  113. ParthKohli
    • 2 years ago
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    Asaan hai!|dw:1365096919950:dw|

  114. shubhamsrg
    • 2 years ago
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    1 baar 1 ladki 1 dukandaar ke paas gayi, bolo, "calculator dikhao" dukaandaar bola, "casio?" ? wo boli, " mai badhiya, aap sunao"!! ^_^

  115. shubhamsrg
    • 2 years ago
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    boli*

  116. ParthKohli
    • 2 years ago
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    Thanks for the wonderful... PJ...

  117. shubhamsrg
    • 2 years ago
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    :)

  118. DLS
    • 2 years ago
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    |dw:1365097203822:dw|

  119. ParthKohli
    • 2 years ago
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    |dw:1365097240971:dw|

  120. DLS
    • 2 years ago
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    thanks

  121. ParthKohli
    • 2 years ago
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    Bahut raat ho gayi hai... 2 AM ho gaya hai. Bye

  122. shubhamsrg
    • 2 years ago
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    5 ovr, 60 runs, last ball tak jayega match! :O TV nahi hai mere paas :'(

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