## anonymous 3 years ago @AriPotta

1. anonymous

2. anonymous

is the second one C?

3. anonymous

4. anonymous

Question 7: A $(8+\sqrt{2})(4-3\sqrt{2}) \rightarrow 32 -24\sqrt{2}+4\sqrt{2}-3\sqrt{2}\sqrt{2}$$32-20\sqrt{2}-3(2) \rightarrow 32-6-20\sqrt{2} \rightarrow 26-20\sqrt{2}$

5. anonymous

thanks guys!

6. anonymous

and with the first one, just multiply the two fractions. 2/3 x 4/5 = 8/15

7. anonymous

8. anonymous

Which of the following is a solution to √x-4+9=6

9. anonymous

x = 17 x = 15 x = 5 x = 3

10. anonymous

@AriPotta

11. anonymous

is that sqrt(x - 4) + 9 = 6?

12. anonymous

x = –3 x = –7 x = 1 x = 13 I put the wrong answer choices

13. anonymous

yes

14. anonymous

ok, so subtract 9 first

15. anonymous

√x-4-3 ?

16. anonymous

sqrt(x - 4) + 9 = 6 sqrt(x - 4) = -3 then square it [sqrt(x - 4)]^2 = -3^2 x - 4 = 9 add 4 x = 13

17. anonymous

i have one more. I gonna see if I can do it

18. anonymous

6√x+1=24

19. anonymous

I got it wrong. i got 88

20. anonymous

x = 17 x = 15 x = 5 x = 3

21. anonymous

divide by 6 6sqrt(x + 1) = 24 sqrt(x + 1) = 4 square it [sqrt(x + 1)]^2 = 4^2 x + 1 = 16 subtract 1 x + 1 = 16 x = 15

22. anonymous