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miah

  • 3 years ago

@AriPotta

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  1. miah
    • 3 years ago
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  2. miah
    • 3 years ago
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    is the second one C?

  3. AriPotta
    • 3 years ago
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  4. Lynncake
    • 3 years ago
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    Question 7: A \[(8+\sqrt{2})(4-3\sqrt{2}) \rightarrow 32 -24\sqrt{2}+4\sqrt{2}-3\sqrt{2}\sqrt{2}\]\[32-20\sqrt{2}-3(2) \rightarrow 32-6-20\sqrt{2} \rightarrow 26-20\sqrt{2}\]

  5. miah
    • 3 years ago
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    thanks guys!

  6. AriPotta
    • 3 years ago
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    and with the first one, just multiply the two fractions. 2/3 x 4/5 = 8/15

  7. miah
    • 3 years ago
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    what about the #6 ?

  8. miah
    • 3 years ago
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    Which of the following is a solution to √x-4+9=6

  9. miah
    • 3 years ago
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    x = 17 x = 15 x = 5 x = 3

  10. miah
    • 3 years ago
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    @AriPotta

  11. AriPotta
    • 3 years ago
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    is that sqrt(x - 4) + 9 = 6?

  12. miah
    • 3 years ago
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    x = –3 x = –7 x = 1 x = 13 I put the wrong answer choices

  13. miah
    • 3 years ago
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    yes

  14. AriPotta
    • 3 years ago
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    ok, so subtract 9 first

  15. miah
    • 3 years ago
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    √x-4-3 ?

  16. AriPotta
    • 3 years ago
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    sqrt(x - 4) + 9 = 6 sqrt(x - 4) = -3 then square it [sqrt(x - 4)]^2 = -3^2 x - 4 = 9 add 4 x = 13

  17. miah
    • 3 years ago
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    i have one more. I gonna see if I can do it

  18. miah
    • 3 years ago
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    6√x+1=24

  19. miah
    • 3 years ago
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    I got it wrong. i got 88

  20. miah
    • 3 years ago
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    x = 17 x = 15 x = 5 x = 3

  21. AriPotta
    • 3 years ago
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    divide by 6 6sqrt(x + 1) = 24 sqrt(x + 1) = 4 square it [sqrt(x + 1)]^2 = 4^2 x + 1 = 16 subtract 1 x + 1 = 16 x = 15

  22. miah
    • 3 years ago
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