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Lynncake
 one year ago
Best ResponseYou've already chosen the best response.1Q11: \[\sqrt{16*5}3\sqrt{9*7}\sqrt{25*5}\sqrt{25*7}=4\sqrt{5}9\sqrt{7}5\sqrt{5}5\sqrt{7}\]\[\sqrt{5}14\sqrt{7}\]The answer to Q11: A

AriPotta
 one year ago
Best ResponseYou've already chosen the best response.0sorry, i can't really help. i'm trying to get my own work done lol. best of luck :]

Lynncake
 one year ago
Best ResponseYou've already chosen the best response.1Q12: \[\frac{ 4 }{ 6\sqrt{7} }*\frac{ 6+\sqrt{7} }{ 6+\sqrt{7} }=\frac{ 4(6+\sqrt{7}) }{ 367 }\]\[\frac{ 24+4\sqrt{7} }{ 29 }\]The answer to Q12: B

Lynncake
 one year ago
Best ResponseYou've already chosen the best response.1I can't give direct answers, but I can work with you through the answer.

Lynncake
 one year ago
Best ResponseYou've already chosen the best response.1In this one \[\sqrt[8]{x^3}\]from the basic analysis that \[\sqrt[]{x}=\sqrt[2]{x}=x^{\frac{ 1 }{ 2 }}\]x is raised to the power of 1 (make it the numerator) and the 2 (make it the denominator) Do you follow?

Lynncake
 one year ago
Best ResponseYou've already chosen the best response.1So what's the answer?
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