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miah

  • 2 years ago

help ?

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  1. miah
    • 2 years ago
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  2. Lynncake
    • 2 years ago
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    Q11: \[\sqrt{16*5}-3\sqrt{9*7}-\sqrt{25*5}-\sqrt{25*7}=4\sqrt{5}-9\sqrt{7}-5\sqrt{5}-5\sqrt{7}\]\[-\sqrt{5}-14\sqrt{7}\]The answer to Q11: A

  3. miah
    • 2 years ago
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    @AriPotta

  4. AriPotta
    • 2 years ago
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    sorry, i can't really help. i'm trying to get my own work done lol. best of luck :]

  5. miah
    • 2 years ago
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    Thanks

  6. Lynncake
    • 2 years ago
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    Q12: \[\frac{ 4 }{ 6-\sqrt{7} }*\frac{ 6+\sqrt{7} }{ 6+\sqrt{7} }=\frac{ 4(6+\sqrt{7}) }{ 36-7 }\]\[\frac{ 24+4\sqrt{7} }{ 29 }\]The answer to Q12: B

  7. miah
    • 2 years ago
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    Last one

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  8. miah
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    @Lynncake

  9. Lynncake
    • 2 years ago
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    I can't give direct answers, but I can work with you through the answer.

  10. miah
    • 2 years ago
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    ohkay

  11. Lynncake
    • 2 years ago
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    In this one \[\sqrt[8]{x^3}\]from the basic analysis that \[\sqrt[]{x}=\sqrt[2]{x}=x^{\frac{ 1 }{ 2 }}\]x is raised to the power of 1 (make it the numerator) and the 2 (make it the denominator) Do you follow?

  12. miah
    • 2 years ago
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    yeah

  13. Lynncake
    • 2 years ago
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    So what's the answer?

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spraguer (Moderator)
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