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anonymous
 3 years ago
12(x5)7=18x103
anonymous
 3 years ago
12(x5)7=18x103

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I tried everything. I distribute and all but after i get this 12x607=18x103

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i Meant 12x607=18x103

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.16x = 36 6x = 30 x = 36/6 = 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you are moving to which side left or right

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.1i moved all of my x's to the left

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and you change the signs

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.1and all of my intergers to the right

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.1change sign by multiply both sides by 1

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.1so you started right, first multiply out the brachets so all thats left is pluses and minuses

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.1then move all of the x values to one side

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.1then move all of the whole numbers to the other side

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.1then divide both sides by whatever's in front of the x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.012(x5)7=18x103 12x607=18x103 12x67=18x103 6x67=103 +67 +67 6x=36 36/6 =6 x=6

Jack1
 3 years ago
Best ResponseYou've already chosen the best response.1in your working yo didnt show that you've x both sides by 1 after you added the 67 to each side, so i know u know what your doing, but its always good to write down that step and show working in an exam situation and otherwise just so it's easier to follow and check errors, but other than that the above is perfect

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know but I can write it here.
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