anonymous
  • anonymous
12(x-5)-7=18x-103
Mathematics
katieb
  • katieb
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Jack1
  • Jack1
solve for x, yeah?
anonymous
  • anonymous
I tried everything. I distribute and all but after i get this 12x60-7=18x-103
anonymous
  • anonymous
i Meant 12x-60-7=18x-103

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Jack1
  • Jack1
12x - 60 - 7 = 18x - 103
Jack1
  • Jack1
-6x - 67 = -103
anonymous
  • anonymous
wait
Jack1
  • Jack1
-6x = -36 6x = 30 x = 36/6 = 6
anonymous
  • anonymous
you are moving to which side left or right
Jack1
  • Jack1
i moved all of my x's to the left
anonymous
  • anonymous
and you change the signs
Jack1
  • Jack1
and all of my intergers to the right
Jack1
  • Jack1
change sign by multiply both sides by -1
Jack1
  • Jack1
so you started right, first multiply out the brachets so all thats left is pluses and minuses
Jack1
  • Jack1
then move all of the x values to one side
Jack1
  • Jack1
then move all of the whole numbers to the other side
Jack1
  • Jack1
then divide both sides by whatever's in front of the x
anonymous
  • anonymous
12(x-5)-7=18x-103 12x-60-7=18x-103 12x-67=18x-103 6x-67=-103 +67 +67 6x=36 36/6 =6 x=6
Jack1
  • Jack1
in your working yo didnt show that you've x both sides by -1 after you added the 67 to each side, so i know u know what your doing, but its always good to write down that step and show working in an exam situation and otherwise just so it's easier to follow and check errors, but other than that the above is perfect
anonymous
  • anonymous
i know but I can write it here.

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