NatalieLove
12(x-5)-7=18x-103
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Jack1
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solve for x, yeah?
NatalieLove
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I tried everything. I distribute and all but after i get this
12x60-7=18x-103
NatalieLove
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i Meant 12x-60-7=18x-103
Jack1
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12x - 60 - 7 = 18x - 103
Jack1
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-6x - 67 = -103
NatalieLove
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wait
Jack1
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-6x = -36
6x = 30
x = 36/6 = 6
NatalieLove
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you are moving to which side left or right
Jack1
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i moved all of my x's to the left
NatalieLove
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and you change the signs
Jack1
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and all of my intergers to the right
Jack1
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change sign by multiply both sides by -1
Jack1
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so you started right, first multiply out the brachets so all thats left is pluses and minuses
Jack1
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then move all of the x values to one side
Jack1
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then move all of the whole numbers to the other side
Jack1
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then divide both sides by whatever's in front of the x
NatalieLove
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12(x-5)-7=18x-103
12x-60-7=18x-103
12x-67=18x-103
6x-67=-103
+67 +67
6x=36
36/6 =6
x=6
Jack1
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in your working yo didnt show that you've x both sides by -1 after you added the 67 to each side, so i know u know what your doing, but its always good to write down that step and show working in an exam situation and otherwise just so it's easier to follow and check errors, but other than that the above is perfect
NatalieLove
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i know but I can write it here.