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Could x=2 @mathstudent55

could that work?

when they intersect i get (-2,6)?

What did you get for the equation of the perpendicular?

i plugged in the one that you had calculated

@Matt.Mawson calculated it, but I think he made a mistake.

Let's start from the beginning.
The given line is:
4x + 3y = 10

Solve it for y to get the slope:
3y = -4x + 10
y = (-4/3)x + 10/3

Yes i get that for my equation as well. and for my perpendicular i calculated y=(3/4)x +1.5

Yes, I have both of those.

for my point of intercept i have .88, 2.16

Yes, I got the same x and y as you.

so how will i find the distance?

The final step is the distance between (0.88, 2.16) and (2,3)

For that distance I get 1.4

yes i have that too... Okay. Thank You!

wlcm