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LucyLu15 Group Title

Does any one know how to find the distance between the point (2,3) and the line 4x + 3y = 10?

  • one year ago
  • one year ago

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  1. mathstudent55 Group Title
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    First, find the equation of the line perpendicular to the given line that passes thorugh (2, 3). Once you have the equation of the perpendicular, solve a system of equations of the two equations to find where the lines intersect. Then, find the distance between the point of intersection and point (2, 3).

    • one year ago
  2. LucyLu15 Group Title
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    Could x=2 @mathstudent55

    • one year ago
  3. LucyLu15 Group Title
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    could that work?

    • one year ago
  4. Matt.Mawson Group Title
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    Ok this is a big pain to solve, but here it is. First put the equation of the line into y = m*x+b format y = (4/3)x + 3.333 The perpendicular line will have slope -3/4 and passes through (2,3) so it's equation will be y = (-3/4)x+4.5 The two lines intersect at (.56,4.08) The triangle with tip (.56,4.08) and right point at (2,3) has base 1.44 and height of 1.08 \[\sqrt{1.44^{2}+1.08^{2}} = 1.8 \] 1.8 is the answer

    • one year ago
  5. LucyLu15 Group Title
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    when they intersect i get (-2,6)?

    • one year ago
  6. mathstudent55 Group Title
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    What did you get for the equation of the perpendicular?

    • one year ago
  7. LucyLu15 Group Title
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    i plugged in the one that you had calculated

    • one year ago
  8. mathstudent55 Group Title
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    @Matt.Mawson calculated it, but I think he made a mistake.

    • one year ago
  9. mathstudent55 Group Title
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    Let's start from the beginning. The given line is: 4x + 3y = 10

    • one year ago
  10. mathstudent55 Group Title
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    Solve it for y to get the slope: 3y = -4x + 10 y = (-4/3)x + 10/3

    • one year ago
  11. mathstudent55 Group Title
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    He made a mistake right in the beginning when he subtracted the 4x from both sides. It should be -4x on the right side, but he wrote 4x.

    • one year ago
  12. LucyLu15 Group Title
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    Yes i get that for my equation as well. and for my perpendicular i calculated y=(3/4)x +1.5

    • one year ago
  13. mathstudent55 Group Title
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    Yes, I have both of those.

    • one year ago
  14. LucyLu15 Group Title
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    for my point of intercept i have .88, 2.16

    • one year ago
  15. mathstudent55 Group Title
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    Yes, I got the same x and y as you.

    • one year ago
  16. LucyLu15 Group Title
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    so how will i find the distance?

    • one year ago
  17. mathstudent55 Group Title
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    The final step is the distance between (0.88, 2.16) and (2,3)

    • one year ago
  18. mathstudent55 Group Title
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    For that distance I get 1.4

    • one year ago
  19. LucyLu15 Group Title
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    yes i have that too... Okay. Thank You!

    • one year ago
  20. mathstudent55 Group Title
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    wlcm

    • one year ago
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