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katlin95

  • 3 years ago

solve for X: square root x^2-x-5=5 A. -5 B. -6 C. 6 D. -5,6

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  1. katlin95
    • 3 years ago
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    the square root is over whole problem

  2. katlin95
    • 3 years ago
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    @jim_thompson5910

  3. tomo
    • 3 years ago
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    do you mean \[\sqrt{x^2-x-5} = 5\]

  4. katlin95
    • 3 years ago
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    yep

  5. katlin95
    • 3 years ago
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    so how would I go about solving it?

  6. katlin95
    • 3 years ago
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    I got -5

  7. jim_thompson5910
    • 3 years ago
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    \[\large \sqrt{x^2-x-5} = 5\] \[\large x^2-x-5 = 5^2\] \[\large x^2-x-5 = 25\] \[\large x^2-x-5 - 25 = 0\] \[\large x^2-x-30 = 0\]

  8. jim_thompson5910
    • 3 years ago
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    I'll let you finish

  9. katlin95
    • 3 years ago
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    yep I got my answer -5 that right?

  10. jim_thompson5910
    • 3 years ago
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    \[\large x^2-x-30 = 0\] \[\large (x+5)(x-6) = 0\]

  11. katlin95
    • 3 years ago
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    -5.6 is the answer?

  12. jim_thompson5910
    • 3 years ago
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    better, it's 6, -5 or -5, 6

  13. katlin95
    • 3 years ago
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    sorry haha that what I ment t type lol

  14. jim_thompson5910
    • 3 years ago
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    that's fine

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