## jazy Group Title I'll put my question in the comments. one year ago one year ago

1. jazy

How would I find AB on here: |dw:1365267611167:dw|

2. jazy

If they give me these length measures. |dw:1365267723624:dw|

3. jazy

They're both right triangles. I have the lengths of the sides, but I want someone to explain how I could find AB, without giving me the answer.

4. AravindG

sorry but the side lengths are not readable :/

5. AravindG

or were they arrows ? :)

6. Rav

This is a matter of using Pythagoras' theorem. a^2 + b^2 = c^2 so name your sides, and then solve for all the things you know. Even if you don't know the side lengths, you can get a formula for the length of AB.

7. jazy

Yeah lol and bad ones too. Do you need the length measures to help me?

8. AravindG

I would recommend you to use similar triangles here

9. jazy

I tried the Pythagoras theorem but neither one of my triangles have 2 side lengths given. :/

10. AravindG

|dw:1365268463728:dw|

11. Rav

If there are no side lengths given then you need to find a formula. Instead of substituting the side length for the variable, just keep the variable in there.

12. jazy

Sorry, my brain is completely blank today when it comes to geometry. I'm not sure what you mean.

13. AravindG

hmm...

14. AravindG

I need to clarify is CBA right angled?

15. jazy

Yes: |dw:1365268759222:dw|

16. AravindG

Are u sure this is only the info given ?

17. jazy

These aren't the ones given to me but maybe they'll work: |dw:1365268927327:dw|

18. AravindG

why not try this ? |dw:1365268967361:dw|

19. AravindG

AB is the only unknown

20. jazy

Ok, I'll try it out on paper first. One sec..

21. AravindG

ok :)

22. AravindG

waiting....

23. jazy

I don't know what wrong with me today :/ So I get: $\tan(A) = \frac{ 104 }{ x} = \frac{ 186 }{ x + 98 }$But how could I solve this with two variables?? o.o

24. Rav

You only have one variable. A is irrelevant, all you want is x.

25. jazy

Oh, ok. So would I cross multiply now to solve for x?

26. Rav

27. AravindG

:)

28. jazy

Ok and thanks(: $\frac{ 104 }{ x } = \frac{ 186 }{ x + 98 } \to 104(x + 98) = 186x \to 104x + 192 = 186x \to 192 = 82x \to 2.34$

29. AravindG

|dw:1365270145268:dw|

30. AravindG

what happened @jazy ?you seem terrible on math today :/

31. jazy

@AravindG I wish I knew. -.- Usually I'm pretty quick to catch on, but I guess today just isn't my day for math. I'll switch subjects for a while to refresh. Thanks for the patience and help, I really do appreciate it. c:

32. AravindG

yw :)