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jazy
 one year ago
Best ResponseYou've already chosen the best response.0How would I find AB on here: dw:1365267611167:dw

jazy
 one year ago
Best ResponseYou've already chosen the best response.0If they give me these length measures. dw:1365267723624:dw

jazy
 one year ago
Best ResponseYou've already chosen the best response.0They're both right triangles. I have the lengths of the sides, but I want someone to explain how I could find AB, without giving me the answer.

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2sorry but the side lengths are not readable :/

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2or were they arrows ? :)

Rav
 one year ago
Best ResponseYou've already chosen the best response.1This is a matter of using Pythagoras' theorem. a^2 + b^2 = c^2 so name your sides, and then solve for all the things you know. Even if you don't know the side lengths, you can get a formula for the length of AB.

jazy
 one year ago
Best ResponseYou've already chosen the best response.0Yeah lol and bad ones too. Do you need the length measures to help me?

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2I would recommend you to use similar triangles here

jazy
 one year ago
Best ResponseYou've already chosen the best response.0I tried the Pythagoras theorem but neither one of my triangles have 2 side lengths given. :/

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2dw:1365268463728:dw

Rav
 one year ago
Best ResponseYou've already chosen the best response.1If there are no side lengths given then you need to find a formula. Instead of substituting the side length for the variable, just keep the variable in there.

jazy
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, my brain is completely blank today when it comes to geometry. I'm not sure what you mean.

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2I need to clarify is CBA right angled?

jazy
 one year ago
Best ResponseYou've already chosen the best response.0Yes: dw:1365268759222:dw

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2Are u sure this is only the info given ?

jazy
 one year ago
Best ResponseYou've already chosen the best response.0These aren't the ones given to me but maybe they'll work: dw:1365268927327:dw

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2why not try this ? dw:1365268967361:dw

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2AB is the only unknown

jazy
 one year ago
Best ResponseYou've already chosen the best response.0Ok, I'll try it out on paper first. One sec..

jazy
 one year ago
Best ResponseYou've already chosen the best response.0I don't know what wrong with me today :/ So I get: \[\tan(A) = \frac{ 104 }{ x} = \frac{ 186 }{ x + 98 }\]But how could I solve this with two variables?? o.o

Rav
 one year ago
Best ResponseYou've already chosen the best response.1You only have one variable. A is irrelevant, all you want is x.

jazy
 one year ago
Best ResponseYou've already chosen the best response.0Oh, ok. So would I cross multiply now to solve for x?

Rav
 one year ago
Best ResponseYou've already chosen the best response.1Yes. Please give your medals to aravind :)

jazy
 one year ago
Best ResponseYou've already chosen the best response.0Ok and thanks(: \[\frac{ 104 }{ x } = \frac{ 186 }{ x + 98 } \to 104(x + 98) = 186x \to 104x + 192 = 186x \to 192 = 82x \to 2.34\]

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2dw:1365270145268:dw

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2what happened @jazy ?you seem terrible on math today :/

jazy
 one year ago
Best ResponseYou've already chosen the best response.0@AravindG I wish I knew. . Usually I'm pretty quick to catch on, but I guess today just isn't my day for math. I'll switch subjects for a while to refresh. Thanks for the patience and help, I really do appreciate it. c:
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