anonymous
  • anonymous
I'll put my question in the comments.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
How would I find AB on here: |dw:1365267611167:dw|
anonymous
  • anonymous
If they give me these length measures. |dw:1365267723624:dw|
anonymous
  • anonymous
They're both right triangles. I have the lengths of the sides, but I want someone to explain how I could find AB, without giving me the answer.

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AravindG
  • AravindG
sorry but the side lengths are not readable :/
AravindG
  • AravindG
or were they arrows ? :)
anonymous
  • anonymous
This is a matter of using Pythagoras' theorem. a^2 + b^2 = c^2 so name your sides, and then solve for all the things you know. Even if you don't know the side lengths, you can get a formula for the length of AB.
anonymous
  • anonymous
Yeah lol and bad ones too. Do you need the length measures to help me?
AravindG
  • AravindG
I would recommend you to use similar triangles here
anonymous
  • anonymous
I tried the Pythagoras theorem but neither one of my triangles have 2 side lengths given. :/
AravindG
  • AravindG
|dw:1365268463728:dw|
anonymous
  • anonymous
If there are no side lengths given then you need to find a formula. Instead of substituting the side length for the variable, just keep the variable in there.
anonymous
  • anonymous
Sorry, my brain is completely blank today when it comes to geometry. I'm not sure what you mean.
AravindG
  • AravindG
hmm...
AravindG
  • AravindG
I need to clarify is CBA right angled?
anonymous
  • anonymous
Yes: |dw:1365268759222:dw|
AravindG
  • AravindG
Are u sure this is only the info given ?
anonymous
  • anonymous
These aren't the ones given to me but maybe they'll work: |dw:1365268927327:dw|
AravindG
  • AravindG
why not try this ? |dw:1365268967361:dw|
AravindG
  • AravindG
AB is the only unknown
anonymous
  • anonymous
Ok, I'll try it out on paper first. One sec..
AravindG
  • AravindG
ok :)
AravindG
  • AravindG
waiting....
anonymous
  • anonymous
I don't know what wrong with me today :/ So I get: \[\tan(A) = \frac{ 104 }{ x} = \frac{ 186 }{ x + 98 }\]But how could I solve this with two variables?? o.o
anonymous
  • anonymous
You only have one variable. A is irrelevant, all you want is x.
anonymous
  • anonymous
Oh, ok. So would I cross multiply now to solve for x?
anonymous
  • anonymous
Yes. Please give your medals to aravind :)
AravindG
  • AravindG
:)
anonymous
  • anonymous
Ok and thanks(: \[\frac{ 104 }{ x } = \frac{ 186 }{ x + 98 } \to 104(x + 98) = 186x \to 104x + 192 = 186x \to 192 = 82x \to 2.34\]
AravindG
  • AravindG
|dw:1365270145268:dw|
AravindG
  • AravindG
what happened @jazy ?you seem terrible on math today :/
anonymous
  • anonymous
@AravindG I wish I knew. -.- Usually I'm pretty quick to catch on, but I guess today just isn't my day for math. I'll switch subjects for a while to refresh. Thanks for the patience and help, I really do appreciate it. c:
AravindG
  • AravindG
yw :)

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