I'll put my question in the comments.

- anonymous

I'll put my question in the comments.

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- schrodinger

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- anonymous

How would I find AB on here:
|dw:1365267611167:dw|

- anonymous

If they give me these length measures.
|dw:1365267723624:dw|

- anonymous

They're both right triangles. I have the lengths of the sides, but I want someone to explain how I could find AB, without giving me the answer.

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## More answers

- AravindG

sorry but the side lengths are not readable :/

- AravindG

or were they arrows ? :)

- anonymous

This is a matter of using Pythagoras' theorem.
a^2 + b^2 = c^2
so name your sides, and then solve for all the things you know. Even if you don't know the side lengths, you can get a formula for the length of AB.

- anonymous

Yeah lol and bad ones too. Do you need the length measures to help me?

- AravindG

I would recommend you to use similar triangles here

- anonymous

I tried the Pythagoras theorem but neither one of my triangles have 2 side lengths given. :/

- AravindG

|dw:1365268463728:dw|

- anonymous

If there are no side lengths given then you need to find a formula. Instead of substituting the side length for the variable, just keep the variable in there.

- anonymous

Sorry, my brain is completely blank today when it comes to geometry. I'm not sure what you mean.

- AravindG

hmm...

- AravindG

I need to clarify is CBA right angled?

- anonymous

Yes:
|dw:1365268759222:dw|

- AravindG

Are u sure this is only the info given ?

- anonymous

These aren't the ones given to me but maybe they'll work:
|dw:1365268927327:dw|

- AravindG

why not try this ?
|dw:1365268967361:dw|

- AravindG

AB is the only unknown

- anonymous

Ok, I'll try it out on paper first. One sec..

- AravindG

ok :)

- AravindG

waiting....

- anonymous

I don't know what wrong with me today :/
So I get:
\[\tan(A) = \frac{ 104 }{ x} = \frac{ 186 }{ x + 98 }\]But how could I solve this with two variables?? o.o

- anonymous

You only have one variable. A is irrelevant, all you want is x.

- anonymous

Oh, ok. So would I cross multiply now to solve for x?

- anonymous

Yes. Please give your medals to aravind :)

- AravindG

:)

- anonymous

Ok and thanks(:
\[\frac{ 104 }{ x } = \frac{ 186 }{ x + 98 } \to 104(x + 98) = 186x \to 104x + 192 = 186x \to 192 = 82x \to 2.34\]

- AravindG

|dw:1365270145268:dw|

- AravindG

what happened @jazy ?you seem terrible on math today :/

- anonymous

@AravindG I wish I knew. -.- Usually I'm pretty quick to catch on, but I guess today just isn't my day for math. I'll switch subjects for a while to refresh. Thanks for the patience and help, I really do appreciate it. c:

- AravindG

yw :)

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