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jazy Group TitleBest ResponseYou've already chosen the best response.0
How would I find AB on here: dw:1365267611167:dw
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
If they give me these length measures. dw:1365267723624:dw
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
They're both right triangles. I have the lengths of the sides, but I want someone to explain how I could find AB, without giving me the answer.
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
sorry but the side lengths are not readable :/
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
or were they arrows ? :)
 one year ago

Rav Group TitleBest ResponseYou've already chosen the best response.1
This is a matter of using Pythagoras' theorem. a^2 + b^2 = c^2 so name your sides, and then solve for all the things you know. Even if you don't know the side lengths, you can get a formula for the length of AB.
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
Yeah lol and bad ones too. Do you need the length measures to help me?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
I would recommend you to use similar triangles here
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
I tried the Pythagoras theorem but neither one of my triangles have 2 side lengths given. :/
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
dw:1365268463728:dw
 one year ago

Rav Group TitleBest ResponseYou've already chosen the best response.1
If there are no side lengths given then you need to find a formula. Instead of substituting the side length for the variable, just keep the variable in there.
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
Sorry, my brain is completely blank today when it comes to geometry. I'm not sure what you mean.
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
I need to clarify is CBA right angled?
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
Yes: dw:1365268759222:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
Are u sure this is only the info given ?
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
These aren't the ones given to me but maybe they'll work: dw:1365268927327:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
why not try this ? dw:1365268967361:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
AB is the only unknown
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
Ok, I'll try it out on paper first. One sec..
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
waiting....
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
I don't know what wrong with me today :/ So I get: \[\tan(A) = \frac{ 104 }{ x} = \frac{ 186 }{ x + 98 }\]But how could I solve this with two variables?? o.o
 one year ago

Rav Group TitleBest ResponseYou've already chosen the best response.1
You only have one variable. A is irrelevant, all you want is x.
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
Oh, ok. So would I cross multiply now to solve for x?
 one year ago

Rav Group TitleBest ResponseYou've already chosen the best response.1
Yes. Please give your medals to aravind :)
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
Ok and thanks(: \[\frac{ 104 }{ x } = \frac{ 186 }{ x + 98 } \to 104(x + 98) = 186x \to 104x + 192 = 186x \to 192 = 82x \to 2.34\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
dw:1365270145268:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
what happened @jazy ?you seem terrible on math today :/
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
@AravindG I wish I knew. . Usually I'm pretty quick to catch on, but I guess today just isn't my day for math. I'll switch subjects for a while to refresh. Thanks for the patience and help, I really do appreciate it. c:
 one year ago
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