## jazy Group Title I'll put my question in the comments. one year ago one year ago

1. jazy Group Title

How would I find AB on here: |dw:1365267611167:dw|

2. jazy Group Title

If they give me these length measures. |dw:1365267723624:dw|

3. jazy Group Title

They're both right triangles. I have the lengths of the sides, but I want someone to explain how I could find AB, without giving me the answer.

4. AravindG Group Title

sorry but the side lengths are not readable :/

5. AravindG Group Title

or were they arrows ? :)

6. Rav Group Title

This is a matter of using Pythagoras' theorem. a^2 + b^2 = c^2 so name your sides, and then solve for all the things you know. Even if you don't know the side lengths, you can get a formula for the length of AB.

7. jazy Group Title

Yeah lol and bad ones too. Do you need the length measures to help me?

8. AravindG Group Title

I would recommend you to use similar triangles here

9. jazy Group Title

I tried the Pythagoras theorem but neither one of my triangles have 2 side lengths given. :/

10. AravindG Group Title

|dw:1365268463728:dw|

11. Rav Group Title

If there are no side lengths given then you need to find a formula. Instead of substituting the side length for the variable, just keep the variable in there.

12. jazy Group Title

Sorry, my brain is completely blank today when it comes to geometry. I'm not sure what you mean.

13. AravindG Group Title

hmm...

14. AravindG Group Title

I need to clarify is CBA right angled?

15. jazy Group Title

Yes: |dw:1365268759222:dw|

16. AravindG Group Title

Are u sure this is only the info given ?

17. jazy Group Title

These aren't the ones given to me but maybe they'll work: |dw:1365268927327:dw|

18. AravindG Group Title

why not try this ? |dw:1365268967361:dw|

19. AravindG Group Title

AB is the only unknown

20. jazy Group Title

Ok, I'll try it out on paper first. One sec..

21. AravindG Group Title

ok :)

22. AravindG Group Title

waiting....

23. jazy Group Title

I don't know what wrong with me today :/ So I get: $\tan(A) = \frac{ 104 }{ x} = \frac{ 186 }{ x + 98 }$But how could I solve this with two variables?? o.o

24. Rav Group Title

You only have one variable. A is irrelevant, all you want is x.

25. jazy Group Title

Oh, ok. So would I cross multiply now to solve for x?

26. Rav Group Title

27. AravindG Group Title

:)

28. jazy Group Title

Ok and thanks(: $\frac{ 104 }{ x } = \frac{ 186 }{ x + 98 } \to 104(x + 98) = 186x \to 104x + 192 = 186x \to 192 = 82x \to 2.34$

29. AravindG Group Title

|dw:1365270145268:dw|

30. AravindG Group Title

what happened @jazy ?you seem terrible on math today :/

31. jazy Group Title

@AravindG I wish I knew. -.- Usually I'm pretty quick to catch on, but I guess today just isn't my day for math. I'll switch subjects for a while to refresh. Thanks for the patience and help, I really do appreciate it. c:

32. AravindG Group Title

yw :)