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jazy

I'll put my question in the comments.

  • one year ago
  • one year ago

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  1. jazy
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    How would I find AB on here: |dw:1365267611167:dw|

    • one year ago
  2. jazy
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    If they give me these length measures. |dw:1365267723624:dw|

    • one year ago
  3. jazy
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    They're both right triangles. I have the lengths of the sides, but I want someone to explain how I could find AB, without giving me the answer.

    • one year ago
  4. AravindG
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    sorry but the side lengths are not readable :/

    • one year ago
  5. AravindG
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    or were they arrows ? :)

    • one year ago
  6. Rav
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    This is a matter of using Pythagoras' theorem. a^2 + b^2 = c^2 so name your sides, and then solve for all the things you know. Even if you don't know the side lengths, you can get a formula for the length of AB.

    • one year ago
  7. jazy
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    Yeah lol and bad ones too. Do you need the length measures to help me?

    • one year ago
  8. AravindG
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    I would recommend you to use similar triangles here

    • one year ago
  9. jazy
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    I tried the Pythagoras theorem but neither one of my triangles have 2 side lengths given. :/

    • one year ago
  10. AravindG
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    |dw:1365268463728:dw|

    • one year ago
  11. Rav
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    If there are no side lengths given then you need to find a formula. Instead of substituting the side length for the variable, just keep the variable in there.

    • one year ago
  12. jazy
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    Sorry, my brain is completely blank today when it comes to geometry. I'm not sure what you mean.

    • one year ago
  13. AravindG
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    hmm...

    • one year ago
  14. AravindG
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    I need to clarify is CBA right angled?

    • one year ago
  15. jazy
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    Yes: |dw:1365268759222:dw|

    • one year ago
  16. AravindG
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    Are u sure this is only the info given ?

    • one year ago
  17. jazy
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    These aren't the ones given to me but maybe they'll work: |dw:1365268927327:dw|

    • one year ago
  18. AravindG
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    why not try this ? |dw:1365268967361:dw|

    • one year ago
  19. AravindG
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    AB is the only unknown

    • one year ago
  20. jazy
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    Ok, I'll try it out on paper first. One sec..

    • one year ago
  21. AravindG
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    ok :)

    • one year ago
  22. AravindG
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    waiting....

    • one year ago
  23. jazy
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    I don't know what wrong with me today :/ So I get: \[\tan(A) = \frac{ 104 }{ x} = \frac{ 186 }{ x + 98 }\]But how could I solve this with two variables?? o.o

    • one year ago
  24. Rav
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    You only have one variable. A is irrelevant, all you want is x.

    • one year ago
  25. jazy
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    Oh, ok. So would I cross multiply now to solve for x?

    • one year ago
  26. Rav
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    Yes. Please give your medals to aravind :)

    • one year ago
  27. AravindG
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    :)

    • one year ago
  28. jazy
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    Ok and thanks(: \[\frac{ 104 }{ x } = \frac{ 186 }{ x + 98 } \to 104(x + 98) = 186x \to 104x + 192 = 186x \to 192 = 82x \to 2.34\]

    • one year ago
  29. AravindG
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    |dw:1365270145268:dw|

    • one year ago
  30. AravindG
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    what happened @jazy ?you seem terrible on math today :/

    • one year ago
  31. jazy
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    @AravindG I wish I knew. -.- Usually I'm pretty quick to catch on, but I guess today just isn't my day for math. I'll switch subjects for a while to refresh. Thanks for the patience and help, I really do appreciate it. c:

    • one year ago
  32. AravindG
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    yw :)

    • one year ago
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