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anonymous
 3 years ago
I'll put my question in the comments.
anonymous
 3 years ago
I'll put my question in the comments.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How would I find AB on here: dw:1365267611167:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If they give me these length measures. dw:1365267723624:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0They're both right triangles. I have the lengths of the sides, but I want someone to explain how I could find AB, without giving me the answer.

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2sorry but the side lengths are not readable :/

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2or were they arrows ? :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This is a matter of using Pythagoras' theorem. a^2 + b^2 = c^2 so name your sides, and then solve for all the things you know. Even if you don't know the side lengths, you can get a formula for the length of AB.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah lol and bad ones too. Do you need the length measures to help me?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2I would recommend you to use similar triangles here

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I tried the Pythagoras theorem but neither one of my triangles have 2 side lengths given. :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If there are no side lengths given then you need to find a formula. Instead of substituting the side length for the variable, just keep the variable in there.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry, my brain is completely blank today when it comes to geometry. I'm not sure what you mean.

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2I need to clarify is CBA right angled?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes: dw:1365268759222:dw

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2Are u sure this is only the info given ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0These aren't the ones given to me but maybe they'll work: dw:1365268927327:dw

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2why not try this ? dw:1365268967361:dw

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2AB is the only unknown

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, I'll try it out on paper first. One sec..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know what wrong with me today :/ So I get: \[\tan(A) = \frac{ 104 }{ x} = \frac{ 186 }{ x + 98 }\]But how could I solve this with two variables?? o.o

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You only have one variable. A is irrelevant, all you want is x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, ok. So would I cross multiply now to solve for x?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes. Please give your medals to aravind :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok and thanks(: \[\frac{ 104 }{ x } = \frac{ 186 }{ x + 98 } \to 104(x + 98) = 186x \to 104x + 192 = 186x \to 192 = 82x \to 2.34\]

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2what happened @jazy ?you seem terrible on math today :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@AravindG I wish I knew. . Usually I'm pretty quick to catch on, but I guess today just isn't my day for math. I'll switch subjects for a while to refresh. Thanks for the patience and help, I really do appreciate it. c:
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