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3logx = (log x)^2
log x (log x - 3) = 0
log x = 0 or log x = 3
x = 1 or e^3

yeah @Kanwar245 has it :)

I meant|dw:1365283288597:dw|

Same thing?

yes I used log rules and then factored log x

actually @Kanwar245 wouldn't x = 1 and x = e

log e^3 = 3

log 1 = 0