Grazes
logx^3=(logx)^2
solve for x



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Kanwar245
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3logx = (log x)^2
log x (log x  3) = 0
log x = 0 or log x = 3
x = 1 or e^3

some_someone
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yeah @Kanwar245 has it :)

Grazes
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I meantdw:1365283288597:dw

Grazes
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Same thing?

Kanwar245
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yes I used log rules and then factored log x

some_someone
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actually @Kanwar245 wouldn't x = 1 and x = e

Kanwar245
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log e^3 = 3

Kanwar245
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log 1 = 0