appleduardo
whats the integral for dx/x^2 + 16 ?



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wio
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Trig sub perhaps?

appleduardo
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i thinks its \[\frac{ \ln (x ^{2} +16)}{ 2 }+C\]

wio
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\[
x=4\tan\theta
\]

wio
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This is it right?\[
\int \frac{dx}{x^2+16}
\]

appleduardo
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yep!

wio
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Wanna do a trig sub. You can't do the \(\ln(\;)\) thing unless the denominator is linear.

wio
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\[
x=4\tan\theta,\,dx=4\sec^2\theta \,d\theta
\]

wio
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Try this substitution and see what happens.

appleduardo
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i'll doit, thanks!