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onegirl Group TitleBest ResponseYou've already chosen the best response.0
@rajathsbhat can u help?
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.0
can you do it if i teach you how to derive e^2x?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
I got 2e^2x is that correct?
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.0
product rule..
 one year ago

kausarsalley Group TitleBest ResponseYou've already chosen the best response.1
what you got when you differentiated the exponent is correct......
 one year ago

kausarsalley Group TitleBest ResponseYou've already chosen the best response.1
do you know the product rule??
 one year ago

kausarsalley Group TitleBest ResponseYou've already chosen the best response.1
this is the product rule..... it says if you have eg.... \[y=uv\] \[\frac{ dy }{ dx }= uv \prime + vu \prime \]
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
can you give an example?
 one year ago

kausarsalley Group TitleBest ResponseYou've already chosen the best response.1
yes...sure eg. \[y= 7xe ^{x ^{2}}\] \[\frac{ dy }{ dx }=7x \times 2xe ^{x ^{2}} +xe ^{x ^{2}} \times 7\]
 one year ago

kausarsalley Group TitleBest ResponseYou've already chosen the best response.1
can you simplify it further from there?????
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
i think so
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
thx for the help
 one year ago

kausarsalley Group TitleBest ResponseYou've already chosen the best response.1
you are welcome.....
 one year ago
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