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Help with Logarithms?

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For #4 this is how I did it....

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Other answers:

(x - 2) log(7) = x * log(5) x * log(7) - x * log(5) = 2 log(7) x [log(7) - log(5)] = 2 log(7) x [log(7) - log(5)] = 2 log(7) x = 2 log(7) / [log(7) - log(5)] = log(49) / log(7/5) ≈ 11.57
#2 *
looks gud :)
For #1 this is how I have done it so far...
16^x-4 = 3^3-x (x-4)log16 = (3-x)log3 xlog16 - 4log16 = 3log3 - xlog3 xlog16 + x log3 = 3log3 + 4log16 x = (3log3 + 4log16) / (log16 + log3)
wats the problem?
it looks fine too :)
I don't know how to finish it though... :(
I feel like I got stuck and I don't know where to go from there.
cannt u type it all into ur calculator now and solve?
I don't have those types of calculators, it was my teacher that tried helping me out with the first one.
u need a calculator to do logs..
i have one though and i can tell u wat the answer is :)
x = (3log3 + 4log16) / (log16 + log3) x = 3.72

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