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Annetta_Martin

  • 2 years ago

Help with Logarithms?

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  1. Annetta_Martin
    • 2 years ago
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  2. Best_Mathematician
    • 2 years ago
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    |dw:1365375002492:dw|

  3. Annetta_Martin
    • 2 years ago
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    For #4 this is how I did it....

  4. Annetta_Martin
    • 2 years ago
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    (x - 2) log(7) = x * log(5) x * log(7) - x * log(5) = 2 log(7) x [log(7) - log(5)] = 2 log(7) x [log(7) - log(5)] = 2 log(7) x = 2 log(7) / [log(7) - log(5)] = log(49) / log(7/5) ≈ 11.57

  5. Annetta_Martin
    • 2 years ago
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    #2 *

  6. HawkCrimson
    • 2 years ago
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    looks gud :)

  7. Annetta_Martin
    • 2 years ago
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    For #1 this is how I have done it so far...

  8. Annetta_Martin
    • 2 years ago
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    16^x-4 = 3^3-x (x-4)log16 = (3-x)log3 xlog16 - 4log16 = 3log3 - xlog3 xlog16 + x log3 = 3log3 + 4log16 x = (3log3 + 4log16) / (log16 + log3)

  9. HawkCrimson
    • 2 years ago
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    wats the problem?

  10. HawkCrimson
    • 2 years ago
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    it looks fine too :)

  11. Annetta_Martin
    • 2 years ago
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    I don't know how to finish it though... :(

  12. Annetta_Martin
    • 2 years ago
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    I feel like I got stuck and I don't know where to go from there.

  13. HawkCrimson
    • 2 years ago
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    cannt u type it all into ur calculator now and solve?

  14. Annetta_Martin
    • 2 years ago
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    I don't have those types of calculators, it was my teacher that tried helping me out with the first one.

  15. HawkCrimson
    • 2 years ago
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    u need a calculator to do logs..

  16. HawkCrimson
    • 2 years ago
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    i have one though and i can tell u wat the answer is :)

  17. HawkCrimson
    • 2 years ago
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    x = (3log3 + 4log16) / (log16 + log3) x = 3.72

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