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dainel40

  • 2 years ago

A baseball team plays in a stadium that holds 51,000 spectators. With ticket prices at $10, the average attendance had been 38,000. When ticket prices were lowered to $8, the average attendance rose to 42,000. Find the demand function (price p as a function of attendance x), assuming it to be linear??

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  1. dainel40
    • 2 years ago
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    I just need to find the equation. i keep getting this and its wrong : p = -1000 x+ 59,000

  2. jim_thompson5910
    • 2 years ago
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    With ticket prices at $10, the average attendance had been 38,000 means x = 38000 p = 10 giving you one point (38000, 10)

  3. jim_thompson5910
    • 2 years ago
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    When ticket prices were lowered to $8, the average attendance rose to 42,000 means x = 42000 p = 8 so another point is (42000, 8)

  4. jim_thompson5910
    • 2 years ago
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    now find the slope of the line through those two points

  5. dainel40
    • 2 years ago
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    yes and i get p = -1000 x+ 59,000

  6. dainel40
    • 2 years ago
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    it says its wrong

  7. jim_thompson5910
    • 2 years ago
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    the slope is way to big

  8. jim_thompson5910
    • 2 years ago
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    m = (y2-y1)/(x2-x1) m = ( 8- 10)/(42000-38000) m = -2/4000 m = -1/2000 So the slope of the line that passes through the two points is -1/2000

  9. dainel40
    • 2 years ago
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    and how u find b?

  10. jim_thompson5910
    • 2 years ago
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    y = mx + b y = (-1/2000)x + b 38000 = (-1/2000)(10) + b solve for b

  11. dainel40
    • 2 years ago
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    im getting b=7600001/200 n i believe thats way too big

  12. jim_thompson5910
    • 2 years ago
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    38000 = (-1/2000)(10) + b 38000 = -1/200 + b 38000 + 1/200 = b 7600000/200 + 1/200 = b 7600001/200 = b b = 7600001/200 b = 38000.005

  13. dainel40
    • 2 years ago
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    so y=(-1/2000)x +760001/200?

  14. dainel40
    • 2 years ago
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    it says its wrong :(

  15. jim_thompson5910
    • 2 years ago
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    try using decimal form instead of fraction form

  16. dainel40
    • 2 years ago
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    (a) Find the demand function (price p as a function of attendance x), assuming it to be linear.

  17. dainel40
    • 2 years ago
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    thats the actual question

  18. jim_thompson5910
    • 2 years ago
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    i know

  19. jim_thompson5910
    • 2 years ago
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    maybe you entered the fraction in wrong, try it in decimal form

  20. dainel40
    • 2 years ago
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    yea it doesn't let me put in decimals

  21. jim_thompson5910
    • 2 years ago
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    ok post a screenshot of what you're inputting

  22. dainel40
    • 2 years ago
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    sec

  23. jim_thompson5910
    • 2 years ago
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    k

  24. dainel40
    • 2 years ago
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    1 Attachment
  25. jim_thompson5910
    • 2 years ago
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    the numbers are different from what you gave me

  26. dainel40
    • 2 years ago
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    yea I just noticed wow.. im sorry

  27. jim_thompson5910
    • 2 years ago
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    it's fine, use the same idea just with these correct values

  28. dainel40
    • 2 years ago
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    Thank you

  29. jim_thompson5910
    • 2 years ago
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    yw

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