A community for students.
Here's the question you clicked on:
 0 viewing
Annetta_Martin
 2 years ago
Help with Logarithms?
Annetta_Martin
 2 years ago
Help with Logarithms?

This Question is Closed

nathan917
 2 years ago
Best ResponseYou've already chosen the best response.0Is there anymore to the question?

Annetta_Martin
 2 years ago
Best ResponseYou've already chosen the best response.0These are some problems I did before it.....

Annetta_Martin
 2 years ago
Best ResponseYou've already chosen the best response.01. log7 + log (n  2) = log 6n log [7(n  2)] = log (6n) 7(n  2) = 6n n = 14 2. log5 (16)  log5 (2t) = log5 (2) log5 (16 / 2t) = log5 (2) 16 / 2t = 2 t = 4 3. log5 m = (1/3) log5 (125) log5 (m) = log5 [(125^(1/3)] m = 125^(1/3) m = 5 4. log y = (1/4) log (16) + (1/2) log (49) log y = log [16^(1/4)] + log [49^(1/2)] =log y = log (2) + log (7) log y = log (2 . 7) y = 14 5. log6 (b^2 + 2) + log6 (2) = 2 log6 [(b^2 + 2) . 2] = 2 (b^2 + 2) . 2 = 6² b^2 + 2 = 18 b^2 = 16 b = 4 or b =  4 6. log3 (5x + 5)  log3 (x^2  1) = 0 log3 [(5x + 5) / (x^2  1)] = 0 (5x + 5) / (x^2  1) = 3^0 5x + 5 = x²  1 x²  5x  6 = 0 x = 6 or x =  1 x = 6 7. log2 (x  2) + 5 = 8  log2 (4) log2 (x  2) + 5 = 8  2 log2 (x  2) = 1 x  2 = 2^1 x = 4

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1365379791371:dw

modphysnoob
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1365379863911:dw

electrokid
 2 years ago
Best ResponseYou've already chosen the best response.0they are inverse of eachother
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.