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Jrivera

  • 3 years ago

Rewrite as a sum : 2sin 8x cos 3x

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  1. InTheTardis
    • 3 years ago
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    Use the product-to-sum identity: sinxcosx = 1/2[sin(x+y)+sin(x-y).

  2. InTheTardis
    • 3 years ago
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    1[sin(8x+3x)+sin(8x-5x)]

  3. InTheTardis
    • 3 years ago
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    sin(11x)+sin(3x)

  4. Jrivera
    • 3 years ago
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    Thank you !!

  5. InTheTardis
    • 3 years ago
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    :)

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