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anonymous
 3 years ago
3x2+10=12
x = 1 and x = 5
x = −1 and x = −5
x = −9 and x = 3
No Solution
anonymous
 3 years ago
3x2+10=12 x = 1 and x = 5 x = −1 and x = −5 x = −9 and x = 3 No Solution

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@AravindG HELP ME PLEASE STEP BY STEP

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[3x2=2\] now we square this.. the only way to get rid of the absoute sign is to square it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or make two equations out of it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok wait spuare the hole thing

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes see the above simplified orm

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left[3x2\right]^2=2^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok wat about the + 10

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I subtracted it from the two sides

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0notice that the right side became 1210=2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where did u get the 12 frm

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where did u get the 12 from

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[3x2+10=12\qquad\text{....given}\\ \qquad\qquad10\quad10 \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok srry im just learning this ok and then gives u this [−3x−2]^2=2^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that is ok. well, this first gives \[3x2=2\] so, we the square it like you just wrote above

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[(3)^2(x2)^2=(2^2)\] notice that the absolute sign has disappeared

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or to avoid squaring, you can remove the abolute sign in two ways...... \[3x2=2\impliesx2={3\over2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my bad... \[\Large{x2=\color{red}{}{2\over3}}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ooh its ok but how did u get that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0divide the two sides by "3"

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[{3x2\over3}={2\over3}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this gives the above form.. now, by definition of ABSOLUTE value, can it ever become negative?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0HEY STOP STOP STOP I WROTE THE PROBLEM DWN WRONG SRRY THIS IS THE PROBLEM −32x + 6 = −12

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok... you mean no "10" in there?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is so much different than what you first asked for

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok.. proceeding similarly, get the absolute quantity on its own...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ik b/c its 2 differnt problems in one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\Large{32x6=12\\\text{divide both sides by 3}\\ 2x6=4\\\text{to get rid of absolute sign, we get two possible answers}\\\;\\ 2x6=4\qquad{\rm AND}\qquad2x6=4\\ 2x=4+6\qquad\qquad\qquad2x=4+6\\ 2x=10\qquad\qquad\qquad\quad2x=2\\ \boxed{x=5}\qquad\qquad\qquad\quad\boxed{x=1}} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0check, plug in "x=" those numbers in the given problem on the left side. That should give you the right side.
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