You have four $1 bills, two $5 bills, five $10 bills, and five $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. Find P($1, then $10).

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You have four $1 bills, two $5 bills, five $10 bills, and five $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. Find P($1, then $10).

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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A. 9/39 B. 5/64 C. 3/80 D. 1/12
is it B?
i think it's b

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Other answers:

There are 16 bills of which 4 are $1. The probability of selecting a $1 on the first selection is 4/16. There would be 15 bills remaining after making the first choice. 5 of these 15 bills would be $10 if a $1 was already selected. Therefore the probability of selecting a $10 bill on the second selection is 5/15. The required probability is found by multiplying 4/16 by 5/15.\[P($1\ then\ $10)=\frac{4}{16}\times \frac{5}{15}=\frac{1}{4}\times \frac{1}{3}=you\ can\ calculate\]

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