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Rohangrr
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The value of the trigonometrical expression \[(4\sin2\ 60^o + 3\tan2\ 30^o – 8 \sin45^ocos 45^o) \ is\]
@kropot72
Rohangrr
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help?/
kropot72
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Just substitute these values:
\[\sin ^{2}60=(\frac{\sqrt{3}}{2})^{2}\]
\[\tan ^{2}30=(\frac{1}{\sqrt{3}})^{2}\]
\[\sin 45=\cos 45=\frac{ \sqrt{2}}{2}\]
Rohangrr
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I didn't get that
Rohangrr
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@kropot72
kropot72
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What part didn't you get? You just need to plug in the values that I gave and simplify.
Rohangrr
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the starting
kropot72
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\[(4\times \frac{3}{4})+\frac{3}{3}-8(\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{2})=?\]
Rohangrr
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1/2
kropot72
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3 + 1 - 4 = ?
Do you want to know how the exact values for the trig ratios are derived?
Rohangrr
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yo if u could do that
Khushal_Shah
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@Rohangrr , kropot72 basically gave you the answer, his work is spot on. If you follow each of this work from each post, you'll get to the right answer, which, as he/she said in their last response, is 0
kropot72
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