## anonymous 3 years ago Trigonometry

1. anonymous

The value of the trigonometrical expression $(4\sin2\ 60^o + 3\tan2\ 30^o – 8 \sin45^ocos 45^o) \ is$ @kropot72

2. anonymous

help?/

3. kropot72

Just substitute these values: $\sin ^{2}60=(\frac{\sqrt{3}}{2})^{2}$ $\tan ^{2}30=(\frac{1}{\sqrt{3}})^{2}$ $\sin 45=\cos 45=\frac{ \sqrt{2}}{2}$

4. anonymous

I didn't get that

5. anonymous

@kropot72

6. kropot72

What part didn't you get? You just need to plug in the values that I gave and simplify.

7. anonymous

the starting

8. kropot72

$(4\times \frac{3}{4})+\frac{3}{3}-8(\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{2})=?$

9. anonymous

1/2

10. kropot72

3 + 1 - 4 = ? Do you want to know how the exact values for the trig ratios are derived?

11. anonymous

yo if u could do that

12. anonymous

@Rohangrr , kropot72 basically gave you the answer, his work is spot on. If you follow each of this work from each post, you'll get to the right answer, which, as he/she said in their last response, is 0

13. kropot72

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