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Rohangrr

  • 3 years ago

Trigonometry

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  1. Rohangrr
    • 3 years ago
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    The value of the trigonometrical expression \[(4\sin2\ 60^o + 3\tan2\ 30^o – 8 \sin45^ocos 45^o) \ is\] @kropot72

  2. Rohangrr
    • 3 years ago
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    help?/

  3. kropot72
    • 3 years ago
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    Just substitute these values: \[\sin ^{2}60=(\frac{\sqrt{3}}{2})^{2}\] \[\tan ^{2}30=(\frac{1}{\sqrt{3}})^{2}\] \[\sin 45=\cos 45=\frac{ \sqrt{2}}{2}\]

  4. Rohangrr
    • 3 years ago
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    I didn't get that

  5. Rohangrr
    • 3 years ago
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    @kropot72

  6. kropot72
    • 3 years ago
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    What part didn't you get? You just need to plug in the values that I gave and simplify.

  7. Rohangrr
    • 3 years ago
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    the starting

  8. kropot72
    • 3 years ago
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    \[(4\times \frac{3}{4})+\frac{3}{3}-8(\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{2})=?\]

  9. Rohangrr
    • 3 years ago
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    1/2

  10. kropot72
    • 3 years ago
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    3 + 1 - 4 = ? Do you want to know how the exact values for the trig ratios are derived?

  11. Rohangrr
    • 3 years ago
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    yo if u could do that

  12. Khushal_Shah
    • 3 years ago
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    @Rohangrr , kropot72 basically gave you the answer, his work is spot on. If you follow each of this work from each post, you'll get to the right answer, which, as he/she said in their last response, is 0

  13. kropot72
    • 3 years ago
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    |dw:1365502988183:dw| |dw:1365502674259:dw|

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