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anonymous
 3 years ago
HEY PLEASE HELP ME! :)
Find the first four terms in the expansion of (x^1/2+1)^30
anonymous
 3 years ago
HEY PLEASE HELP ME! :) Find the first four terms in the expansion of (x^1/2+1)^30

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RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2use this : 30C0 (x^1/2)^30(1)^0 + 30C1 (x^1/2)^(301) (1)^1 + 30C2 (x^1/2)^(302) (1)^2 + 30C3 (x^1/2)^(303) (1)^3 calculate and simplify it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait im confused do you think you can write it out on paper and attach it? im sorry and i understand if you cannot.

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2do know about combination ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh wait! i think i get it! but do i go all the way to thirty? thats whats confusing me?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2the general formula of combination is dw:1365545267017:dw do u know about factorial :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh wait! i do know about it loll what would be n and what would be r?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2actually, n and r are natural number

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so how would i use the formula?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2well, first u have to know about factorial defined n! = n*(n1)*(n2)*... 3 . 2. 1 an example : 4! = 4 . 3 . 2 . 1 = 24 so far so good ?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2ah, as extra info defined 0! = 1 nah, let's going to combination above 30C0 = 30!/(300)!0! = 30!/30!*1 = 30!/30! = 1, right ?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2so, what is the 30C1 ? :) try

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do i go all the way down until i get to 1?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2so, so on u can calculation of 30C2 and 30C3 right

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2ok, now we have the other problem about exponent

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2look, that i wrote expression about 1^0, 1^1, 1^2, 1^3. these are be 1 right ? and whatever if multiplied by 1 be its self, right ?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2then for simplify of (x^1/2)^30, u can use the property of exponent : (a^m)^n = a^(m*n) so, (x^1/2)^30 = x^16, right ?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2then so on, u have to simplify about (x^(1/2))^(301) = (x^(1/2))^(29) = x^(29/2) = sqrt(x^29) or u can modif again be sqrt(x^28 * x) = sqrt(x^28) sqrt(x) = (x^(28/2)) * sqrt(x) = x^14 * sqrt(x)

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2it just simplification in radical form to exponential form

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2or just one expression sqrt(x^29) only

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.2now, what about u with (x^1/2)^(302) (1)^2 = ... ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh!! okay i understand! thank you very much!!!!
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