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 one year ago
HEY PLEASE HELP ME! :)
Find the first four terms in the expansion of (x^1/2+1)^30
 one year ago
HEY PLEASE HELP ME! :) Find the first four terms in the expansion of (x^1/2+1)^30

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RadEn
 one year ago
Best ResponseYou've already chosen the best response.2use this : 30C0 (x^1/2)^30(1)^0 + 30C1 (x^1/2)^(301) (1)^1 + 30C2 (x^1/2)^(302) (1)^2 + 30C3 (x^1/2)^(303) (1)^3 calculate and simplify it

natasha.aries
 one year ago
Best ResponseYou've already chosen the best response.0wait im confused do you think you can write it out on paper and attach it? im sorry and i understand if you cannot.

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2do know about combination ?

natasha.aries
 one year ago
Best ResponseYou've already chosen the best response.0oh wait! i think i get it! but do i go all the way to thirty? thats whats confusing me?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2the general formula of combination is dw:1365545267017:dw do u know about factorial :)

natasha.aries
 one year ago
Best ResponseYou've already chosen the best response.0oh wait! i do know about it loll what would be n and what would be r?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2actually, n and r are natural number

natasha.aries
 one year ago
Best ResponseYou've already chosen the best response.0so how would i use the formula?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2well, first u have to know about factorial defined n! = n*(n1)*(n2)*... 3 . 2. 1 an example : 4! = 4 . 3 . 2 . 1 = 24 so far so good ?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2ah, as extra info defined 0! = 1 nah, let's going to combination above 30C0 = 30!/(300)!0! = 30!/30!*1 = 30!/30! = 1, right ?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2so, what is the 30C1 ? :) try

natasha.aries
 one year ago
Best ResponseYou've already chosen the best response.0do i go all the way down until i get to 1?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2so, so on u can calculation of 30C2 and 30C3 right

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2ok, now we have the other problem about exponent

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2look, that i wrote expression about 1^0, 1^1, 1^2, 1^3. these are be 1 right ? and whatever if multiplied by 1 be its self, right ?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2then for simplify of (x^1/2)^30, u can use the property of exponent : (a^m)^n = a^(m*n) so, (x^1/2)^30 = x^16, right ?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2then so on, u have to simplify about (x^(1/2))^(301) = (x^(1/2))^(29) = x^(29/2) = sqrt(x^29) or u can modif again be sqrt(x^28 * x) = sqrt(x^28) sqrt(x) = (x^(28/2)) * sqrt(x) = x^14 * sqrt(x)

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2it just simplification in radical form to exponential form

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2or just one expression sqrt(x^29) only

RadEn
 one year ago
Best ResponseYou've already chosen the best response.2now, what about u with (x^1/2)^(302) (1)^2 = ... ?

natasha.aries
 one year ago
Best ResponseYou've already chosen the best response.0ohh!! okay i understand! thank you very much!!!!
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