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HEY PLEASE HELP ME! :)
Find the first four terms in the expansion of (x^1/2+1)^30
 one year ago
 one year ago
HEY PLEASE HELP ME! :) Find the first four terms in the expansion of (x^1/2+1)^30
 one year ago
 one year ago

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RadEnBest ResponseYou've already chosen the best response.2
use this : 30C0 (x^1/2)^30(1)^0 + 30C1 (x^1/2)^(301) (1)^1 + 30C2 (x^1/2)^(302) (1)^2 + 30C3 (x^1/2)^(303) (1)^3 calculate and simplify it
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
wait im confused do you think you can write it out on paper and attach it? im sorry and i understand if you cannot.
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
do know about combination ?
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
oh wait! i think i get it! but do i go all the way to thirty? thats whats confusing me?
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
the general formula of combination is dw:1365545267017:dw do u know about factorial :)
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
oh wait! i do know about it loll what would be n and what would be r?
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
actually, n and r are natural number
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
so how would i use the formula?
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
well, first u have to know about factorial defined n! = n*(n1)*(n2)*... 3 . 2. 1 an example : 4! = 4 . 3 . 2 . 1 = 24 so far so good ?
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
ah, as extra info defined 0! = 1 nah, let's going to combination above 30C0 = 30!/(300)!0! = 30!/30!*1 = 30!/30! = 1, right ?
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
so, what is the 30C1 ? :) try
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
do i go all the way down until i get to 1?
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
so, so on u can calculation of 30C2 and 30C3 right
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
ok, now we have the other problem about exponent
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
look, that i wrote expression about 1^0, 1^1, 1^2, 1^3. these are be 1 right ? and whatever if multiplied by 1 be its self, right ?
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
then for simplify of (x^1/2)^30, u can use the property of exponent : (a^m)^n = a^(m*n) so, (x^1/2)^30 = x^16, right ?
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
then so on, u have to simplify about (x^(1/2))^(301) = (x^(1/2))^(29) = x^(29/2) = sqrt(x^29) or u can modif again be sqrt(x^28 * x) = sqrt(x^28) sqrt(x) = (x^(28/2)) * sqrt(x) = x^14 * sqrt(x)
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
it just simplification in radical form to exponential form
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
or just one expression sqrt(x^29) only
 one year ago

RadEnBest ResponseYou've already chosen the best response.2
now, what about u with (x^1/2)^(302) (1)^2 = ... ?
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
ohh!! okay i understand! thank you very much!!!!
 one year ago
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