anonymous
  • anonymous
An alloy has Fe, Co , Mo in a composition of 71%, 12%, 17% respectively. How many cobalt atoms are there in a cylinder of radius 2.5 cm and length 10 cm .The density of the alloy is 8.2 g/ml.[At.wt Co=59]
Chemistry
jamiebookeater
  • jamiebookeater
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shubhamsrg
  • shubhamsrg
mass= density * volume density is given volume = pi r^2 h fine mass 12% of mass is the final answer use appropriate units.
shubhamsrg
  • shubhamsrg
find*
anonymous
  • anonymous
oh.. we should take v of cylinder as volume?

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shubhamsrg
  • shubhamsrg
yep
anonymous
  • anonymous
and they've asked number of cobalt atoms..how is that 12% of mass?
shubhamsrg
  • shubhamsrg
ahh okay 12% of that = mass of cobalt atoms in 1 mole of cobalt = avagadros no. atoms in given mass = ?
anonymous
  • anonymous
12 % of that? what is that? no.of atoms? or no.of moles?
anonymous
  • anonymous
looks like 12% by mass
shubhamsrg
  • shubhamsrg
12% of that , that'll give mass of cobalt in the compound
anonymous
  • anonymous
what is 'that'?
anonymous
  • anonymous
"that" is the mass of the cylinder I think
shubhamsrg
  • shubhamsrg
that is mass of the compound in the given volume -_-
anonymous
  • anonymous
ok so mass of the alloy..right?
shubhamsrg
  • shubhamsrg
yo B|
anonymous
  • anonymous
look..im sorry if u feel im dumb..but hw am i supposed 2 find mass of alloy?
shubhamsrg
  • shubhamsrg
mass = density * volume -_-
anonymous
  • anonymous
Volume? again volume of cylinder?
anonymous
  • anonymous
volume =pi*radius^2*height
anonymous
  • anonymous
@ Peter14 I KNOW THAT...im askin if volume of alloy is same as volume of cylinder..
anonymous
  • anonymous
yes, because the alloy is in the shape of the cylinder
shubhamsrg
  • shubhamsrg
the allow is in in the cylinder, so there volumes must be equated
anonymous
  • anonymous
oh ok...k i got this..i have 2 more...can i post them now??
anonymous
  • anonymous
sure shub, you take one, i'll take the other
shubhamsrg
  • shubhamsrg
lol.. :D (Y)
anonymous
  • anonymous
dont worry i can only post one-by-one...
anonymous
  • anonymous
start separate threads
anonymous
  • anonymous
One-by-one is easier for me..one itself is hard to understand..2 means gone!
anonymous
  • anonymous
ok, that works

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