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Can anyone explain how to solve(factor) this?

Mathematics
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\[16s ^{4} - 81\]
(4s^2-9)(4s^2+9)
a^2+b^2=(a+b)(a-b) hint: touseii did not give you the complete factoriazation. 4s^2-9 can still be factored.

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Other answers:

(2s - 3)(2s + 3) ? @inkyvoyd
yeah touseii.
would it be (2s - 3)(2s + 3)^2 because that way you get the original binomial?
no. It'd be (2s-3)(2s+3)(4s^2+9)
ohh okay i understand
irreducible (with complex numbers) factorization would be \((2s-3)(2s+3)(2s-3i)(2s+3i)\)
okay makes sense thanks(:
np xD
Thanks a lot!!!
Welcome(: but it was @inkyvoyd who really helped

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