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RH

  • 3 years ago

Can anyone explain how to solve(factor) this?

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  1. RH
    • 3 years ago
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    \[16s ^{4} - 81\]

  2. touseii45
    • 3 years ago
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    (4s^2-9)(4s^2+9)

  3. inkyvoyd
    • 3 years ago
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    a^2+b^2=(a+b)(a-b) hint: touseii did not give you the complete factoriazation. 4s^2-9 can still be factored.

  4. touseii45
    • 3 years ago
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    (2s - 3)(2s + 3) ? @inkyvoyd

  5. inkyvoyd
    • 3 years ago
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    yeah touseii.

  6. touseii45
    • 3 years ago
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    would it be (2s - 3)(2s + 3)^2 because that way you get the original binomial?

  7. inkyvoyd
    • 3 years ago
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    no. It'd be (2s-3)(2s+3)(4s^2+9)

  8. touseii45
    • 3 years ago
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    ohh okay i understand

  9. inkyvoyd
    • 3 years ago
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    irreducible (with complex numbers) factorization would be \((2s-3)(2s+3)(2s-3i)(2s+3i)\)

  10. touseii45
    • 3 years ago
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    okay makes sense thanks(:

  11. inkyvoyd
    • 3 years ago
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    np xD

  12. RH
    • 3 years ago
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    Thanks a lot!!!

  13. touseii45
    • 3 years ago
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    Welcome(: but it was @inkyvoyd who really helped

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