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ethompsonn

  • one year ago

What is the solution set of (x - 2)(x - 3) = 2?

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  1. ethompsonn
    • one year ago
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    @pooja195 ?

  2. hedyeh99
    • one year ago
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    \[x ^{2}-3x-2x+9=2\]

  3. hedyeh99
    • one year ago
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    Now, simplfiy

  4. ethompsonn
    • one year ago
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    uuuuhh

  5. hedyeh99
    • one year ago
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    Do you understand so far?

  6. ethompsonn
    • one year ago
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    noo

  7. hedyeh99
    • one year ago
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    https://www.khanacademy.org/math/algebra/polynomials/multiplying_polynomials/v/multiplying-binomials Watch this, it will help you understand :)

  8. radar
    • one year ago
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    |dw:1365627809851:dw|

  9. ethompsonn
    • one year ago
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    anser is 2,3?

  10. radar
    • one year ago
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    \[x ^{2}-5x + 6 =2\]

  11. Andalite
    • one year ago
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    (x-2) (x-3) = 2 Expand is x2 -3x-2x +6 =2 X2-5x+6= 2 X2-5x= 2-6 X2-5x +4 = 0 (x-1) (x-4)=0 therefore x is 1 or 4

  12. radar
    • one year ago
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    \[x ^{2}-5x+4=0\]

  13. radar
    • one year ago
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    Looks Andalite nailed it.

  14. Andalite
    • one year ago
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    Thanks lol

  15. ethompsonn
    • one year ago
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    What is the solution set of 7x2 + 3x = 0? @Andalite help?

  16. Andalite
    • one year ago
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    Is that 7 times 2 or 7x2?

  17. ethompsonn
    • one year ago
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    7^2

  18. ethompsonn
    • one year ago
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    *7x^2

  19. Andalite
    • one year ago
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    14+3x =0 3x=-14 X=-14 divided by 3 X= -4 and two thirds (2 over 3)

  20. ethompsonn
    • one year ago
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    {0, 3/7} {0, -3/7} {0, -4/7} MY OPTIONS

  21. radar
    • one year ago
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    7x^2 + 3x=0 x(7x + 3)=0 x=0 x=-3/7

  22. ethompsonn
    • one year ago
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    oooo i get it thanks:)

  23. radar
    • one year ago
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    Geat! Good luck with these.

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