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If you bought a car at $1900 which depreciates 20% each year, what will it be worth after 4 years? A. $578 B. $778 C. $988 D. $1,588

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A = P(1 - r)^t A = 1900(1 - 0.2)^4 A = ???

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Other answers:

so it's B
How much will $600 amount to be if it is invested at 10% interest compounded semiannually (two times a year) for 4 years? A. $886.47 B. $952.40 C. $1063.20 D. $1168.17
A = P(1+r/n)^(n*t) plug in P = 600 r = 0.10 n = 2 t = 4
one sec about to solve it
If the current value of a property is $20,000 and its value is increasing at 8% per year. Find the expression for the value after t years. A. $20,000(1.08)t B. $20,000(1.8)t C. $20,000(0.92)t D. $20,000(1.18)t
886 is close, it should be 886.47, but you got the idea
for this last one, you got ???
yep I knew that I new it was a lol
for last one I got C
1+r = 1+0.08 = 1.08, so it should be A
you would do 1-r = 1-0.8 = 0.92 if it were decreasing, but it's INCREASING
okay last one: Which of the following functions increases, going upwards from left to right on a graph? A. y = 2(1/3)x B. y = -2(3)x C. y = 2x + 6 D. y = 3(1/2)x
you tell me
nope, this is a decreasing exponential function
if it were positive, then it would be increasing
yep so that would make it B, because its a negative right
it can't be B because B is decreasing
if B was positive (it's not), then it would be increasing
oh okay, then it must be A
A isn't it for the same reason as D
so you can probably guess what it must be lol
c lol:)
@jim_thompson5910 can you help me with this assignment, im very confused.
sry don't have enough time to do the whole thing
could u possibly tomorrow:)?
i might have more time tomorrow

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