Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
A mechanism on Earth used to shoot down geosynchronous satellites that house laserbased weapons is
finally perfected and propels golf balls at 0.94c.
a) How far will a detector riding with the golf ball initially measure the distance to the satellite?
[Geosynchronous satellites are placed 3.58x104
km above the surface of the Earth.]
b) How much time will it take the golf ball to make the journey to the satellite in the Earth’s frame?
How much time will it take in the golf ball’s frame?
 one year ago
 one year ago
A mechanism on Earth used to shoot down geosynchronous satellites that house laserbased weapons is finally perfected and propels golf balls at 0.94c. a) How far will a detector riding with the golf ball initially measure the distance to the satellite? [Geosynchronous satellites are placed 3.58x104 km above the surface of the Earth.] b) How much time will it take the golf ball to make the journey to the satellite in the Earth’s frame? How much time will it take in the golf ball’s frame?
 one year ago
 one year ago

This Question is Closed

modphysnoobBest ResponseYou've already chosen the best response.0
@Jemurray3 do I use length contraction on this? if so , how?
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
Yes, for the first part. As straightforwardly as you possibly could... \[ L = L_0 \sqrt{1v^2/c^2} \]
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.0
so L0 would be 3.58x10^4 ?
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
Yes, the proper distance is measured in the earth frame because the geosynchronous satellites are at rest relative to the earth.
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.0
for b) do I do just normal calcuation using t= l/v then lorentz transform that t?
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
Yes. Alternatively, you could divide the contracted distance by the velocity.
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.0
oh I see, that works too Thank you for your help
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.