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aussy123 Group Title

CAN SOMEONE PLEASE HELP ME!! Convert x 2 + y 2 = 8 to a polar equation. r = 4 r² = 8 r² = 64

  • one year ago
  • one year ago

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  1. galacticwavesXX Group Title
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    is r the given?

    • one year ago
  2. aussy123 Group Title
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    yes r is 8 its based off the formula x^2+y^2=8

    • one year ago
  3. aussy123 Group Title
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    i think its the last one r^2=64 r=8

    • one year ago
  4. galacticwavesXX Group Title
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    x^2+y^2=8 ==> r^2=8

    • one year ago
  5. galacticwavesXX Group Title
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    how can r^2 be both 8 and 64?

    • one year ago
  6. galacticwavesXX Group Title
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    r^2=8

    • one year ago
  7. aussy123 Group Title
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    |dw:1365741494311:dw|

    • one year ago
  8. galacticwavesXX Group Title
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    r^3=64

    • one year ago
  9. aussy123 Group Title
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    8^2=64

    • one year ago
  10. galacticwavesXX Group Title
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    no but when you are converting to a polar equation \[r=\sqrt{x^2+y^2}\]

    • one year ago
  11. galacticwavesXX Group Title
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    therefore \[r^2=x^2+y^2\]

    • one year ago
  12. galacticwavesXX Group Title
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    so you are replacing the \[x^2+y^2 \]

    • one year ago
  13. galacticwavesXX Group Title
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    with \[r^2\]

    • one year ago
  14. aussy123 Group Title
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    r^2=8

    • one year ago
  15. aussy123 Group Title
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    ?

    • one year ago
  16. galacticwavesXX Group Title
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    yes you are converting from a rectangular equation to a polar equation

    • one year ago
  17. galacticwavesXX Group Title
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    that's what is stated in the question to do

    • one year ago
  18. aussy123 Group Title
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    thx

    • one year ago
  19. galacticwavesXX Group Title
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    but if you teacher wants r itself then r is \[r=2\sqrt{2}\]

    • one year ago
  20. galacticwavesXX Group Title
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    r cant be 4 because you have are taking the root of 8 not halving it

    • one year ago
  21. aussy123 Group Title
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    ok

    • one year ago
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