aussy123
CAN SOMEONE PLEASE HELP ME!!
Convert x 2 + y 2 = 8 to a polar equation.
r = 4
r² = 8
r² = 64



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galacticwavesXX
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is r the given?

aussy123
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yes r is 8
its based off the formula x^2+y^2=8

aussy123
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i think its the last one
r^2=64
r=8

galacticwavesXX
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x^2+y^2=8 ==> r^2=8

galacticwavesXX
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how can r^2 be both 8 and 64?

galacticwavesXX
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r^2=8

aussy123
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dw:1365741494311:dw

galacticwavesXX
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r^3=64

aussy123
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8^2=64

galacticwavesXX
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no but when you are converting to a polar equation \[r=\sqrt{x^2+y^2}\]

galacticwavesXX
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therefore \[r^2=x^2+y^2\]

galacticwavesXX
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so you are replacing the \[x^2+y^2 \]

galacticwavesXX
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with \[r^2\]

aussy123
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r^2=8

aussy123
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?

galacticwavesXX
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yes you are converting from a rectangular equation to a polar equation

galacticwavesXX
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that's what is stated in the question to do

aussy123
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thx

galacticwavesXX
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but if you teacher wants r itself then r is \[r=2\sqrt{2}\]

galacticwavesXX
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r cant be 4 because you have are taking the root of 8 not halving it

aussy123
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ok