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aussy123 Group Title

Convert theta=60 degrees to a Cartesian equation.

  • one year ago
  • one year ago

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  1. trogdortheburninator Group Title
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    You need a length for this to make any sense

    • one year ago
  2. aussy123 Group Title
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    This is all that is given.

    • one year ago
  3. trogdortheburninator Group Title
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    wait, do you mean rotate whatever you're given by 60 degrees?

    • one year ago
  4. aussy123 Group Title
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    I dont know what there are asking for. This is just really exhausting and confusing. They dont really elaborate on anything.

    • one year ago
  5. galacticwavesXX Group Title
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    guess its just \[x=rcos \theta y=rsin \theta \]

    • one year ago
  6. aussy123 Group Title
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    x=sqrt.(3y)

    • one year ago
  7. aussy123 Group Title
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    \[x=\sqrt{3y}\]

    • one year ago
  8. galacticwavesXX Group Title
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    is that the given? Could you type all the that is given for the problem?

    • one year ago
  9. aussy123 Group Title
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    Ill put it in the attachment

    • one year ago
  10. galacticwavesXX Group Title
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    ok that's better

    • one year ago
  11. aussy123 Group Title
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    • one year ago
    1 Attachment
  12. galacticwavesXX Group Title
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    wow that's confusing but i would go with a

    • one year ago
  13. galacticwavesXX Group Title
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    well the 1st one

    • one year ago
  14. galacticwavesXX Group Title
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    what math class is this?

    • one year ago
  15. aussy123 Group Title
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    Pre-Cal

    • one year ago
  16. galacticwavesXX Group Title
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    its the 2nd option. That is the answer

    • one year ago
  17. galacticwavesXX Group Title
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    \[x=\sqrt{3y}\]

    • one year ago
  18. oldrin.bataku Group Title
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    |dw:1365743877178:dw| Notice we have two points, \((0,0)\) and \((\frac12,\frac{\sqrt3}2)\)... can you determine a linear equation now?

    • one year ago
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