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aussy123

  • 3 years ago

Convert theta=60 degrees to a Cartesian equation.

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  1. trogdortheburninator
    • 3 years ago
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    You need a length for this to make any sense

  2. aussy123
    • 3 years ago
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    This is all that is given.

  3. trogdortheburninator
    • 3 years ago
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    wait, do you mean rotate whatever you're given by 60 degrees?

  4. aussy123
    • 3 years ago
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    I dont know what there are asking for. This is just really exhausting and confusing. They dont really elaborate on anything.

  5. galacticwavesXX
    • 3 years ago
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    guess its just \[x=rcos \theta y=rsin \theta \]

  6. aussy123
    • 3 years ago
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    x=sqrt.(3y)

  7. aussy123
    • 3 years ago
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    \[x=\sqrt{3y}\]

  8. galacticwavesXX
    • 3 years ago
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    is that the given? Could you type all the that is given for the problem?

  9. aussy123
    • 3 years ago
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    Ill put it in the attachment

  10. galacticwavesXX
    • 3 years ago
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    ok that's better

  11. aussy123
    • 3 years ago
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    1 Attachment
  12. galacticwavesXX
    • 3 years ago
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    wow that's confusing but i would go with a

  13. galacticwavesXX
    • 3 years ago
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    well the 1st one

  14. galacticwavesXX
    • 3 years ago
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    what math class is this?

  15. aussy123
    • 3 years ago
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    Pre-Cal

  16. galacticwavesXX
    • 3 years ago
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    its the 2nd option. That is the answer

  17. galacticwavesXX
    • 3 years ago
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    \[x=\sqrt{3y}\]

  18. oldrin.bataku
    • 3 years ago
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    |dw:1365743877178:dw| Notice we have two points, \((0,0)\) and \((\frac12,\frac{\sqrt3}2)\)... can you determine a linear equation now?

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