aussy123
Convert theta=60 degrees to a Cartesian equation.



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trogdortheburninator
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You need a length for this to make any sense

aussy123
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This is all that is given.

trogdortheburninator
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wait, do you mean rotate whatever you're given by 60 degrees?

aussy123
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I dont know what there are asking for. This is just really exhausting and confusing. They dont really elaborate on anything.

galacticwavesXX
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guess its just \[x=rcos \theta y=rsin \theta \]

aussy123
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x=sqrt.(3y)

aussy123
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\[x=\sqrt{3y}\]

galacticwavesXX
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is that the given?
Could you type all the that is given for the problem?

aussy123
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Ill put it in the attachment

galacticwavesXX
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ok that's better

aussy123
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galacticwavesXX
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wow that's confusing but i would go with a

galacticwavesXX
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well the 1st one

galacticwavesXX
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what math class is this?

aussy123
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PreCal

galacticwavesXX
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its the 2nd option. That is the answer

galacticwavesXX
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\[x=\sqrt{3y}\]

oldrin.bataku
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dw:1365743877178:dw
Notice we have two points, \((0,0)\) and \((\frac12,\frac{\sqrt3}2)\)... can you determine a linear equation now?