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(sin theta - 1) (5 cos theta + 3) =0

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(sin theta - 1) (5 cos theta + 3) =0 then sin theta - 1 = 0 sin thate = 1 theta = 90 degree and also 5 cos theta + 3 = 0 5 cos theta = -3 cos theta = -3/5 theta = arc cos (-3/5) use your calculator!
how come you can do it in 2 separate parts? surely you cannot leave out half the equation? or can you?

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because multiplication both of them equals zero.., then one and second of them equals zero too!
ahh yes thanksss so much!!!
your welcome

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