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Sophiel44
(sin theta - 1) (5 cos theta + 3) =0
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(sin theta - 1) (5 cos theta + 3) =0 then sin theta - 1 = 0 sin thate = 1 theta = 90 degree and also 5 cos theta + 3 = 0 5 cos theta = -3 cos theta = -3/5 theta = arc cos (-3/5) use your calculator!
how come you can do it in 2 separate parts? surely you cannot leave out half the equation? or can you?
because multiplication both of them equals zero.., then one and second of them equals zero too!
ahh yes thanksss so much!!!