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ValentinaT
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Can someone help me create a problem that has a binomial which IS a factor of the polynomial being divided?
 one year ago
 one year ago
ValentinaT Group Title
Can someone help me create a problem that has a binomial which IS a factor of the polynomial being divided?
 one year ago
 one year ago

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Mertsj Group TitleBest ResponseYou've already chosen the best response.0
If 2(3)=6 what is 6/3?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Is 3 a factor of 6?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
So perhaps we could use that idea and apply it to binomials so we end up with a polynomial that has a binomial factor.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Make up a binomial and post it.
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
y = 2x + 10
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Make up one which is not factorable.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
See why you can't get help. I have been trying to help you for more than 2 hours and you have disappeared yet again.
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
Sorry, I keep forgetting to check back into Openstudy.
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
A non factorable binomial could be \[v^{2} + 16\]
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Make up a second binomial
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
\[(x  1)^{2}\]
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
That is a binomial squared. What is the matter with something simple like x+2 or something?
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
Okay, x + 2
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Multiply your two binomials.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Use the same variable in both. Lose the v and put x
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
Could you hold on please, I have to make a short phone call?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
I'm outta here.
 one year ago
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