ValentinaT
Can someone help me create a problem that has a binomial which IS a factor of the polynomial being divided?



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Mertsj
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If 2(3)=6 what is 6/3?

ValentinaT
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2.

Mertsj
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Is 3 a factor of 6?

ValentinaT
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Yes.

Mertsj
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So perhaps we could use that idea and apply it to binomials so we end up with a polynomial that has a binomial factor.

Mertsj
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Make up a binomial and post it.

ValentinaT
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y = 2x + 10

Mertsj
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Make up one which is not factorable.

Mertsj
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See why you can't get help. I have been trying to help you for more than 2 hours and you have disappeared yet again.

ValentinaT
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Sorry, I keep forgetting to check back into Openstudy.

ValentinaT
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A non factorable binomial could be \[v^{2} + 16\]

Mertsj
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Make up a second binomial

ValentinaT
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\[(x  1)^{2}\]

Mertsj
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That is a binomial squared. What is the matter with something simple like x+2 or something?

ValentinaT
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Okay, x + 2

Mertsj
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Multiply your two binomials.

Mertsj
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Use the same variable in both. Lose the v and put x

ValentinaT
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Could you hold on please, I have to make a short phone call?

Mertsj
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I'm outta here.