## ValentinaT 2 years ago Can someone help me create a problem that has a binomial which IS a factor of the polynomial being divided?

1. Mertsj

If 2(3)=6 what is 6/3?

2. ValentinaT

2.

3. Mertsj

Is 3 a factor of 6?

4. ValentinaT

Yes.

5. Mertsj

So perhaps we could use that idea and apply it to binomials so we end up with a polynomial that has a binomial factor.

6. Mertsj

Make up a binomial and post it.

7. ValentinaT

y = 2x + 10

8. Mertsj

Make up one which is not factorable.

9. Mertsj

See why you can't get help. I have been trying to help you for more than 2 hours and you have disappeared yet again.

10. ValentinaT

Sorry, I keep forgetting to check back into Openstudy.

11. ValentinaT

A non factorable binomial could be \[v^{2} + 16\]

12. Mertsj

Make up a second binomial

13. ValentinaT

\[(x - 1)^{2}\]

14. Mertsj

That is a binomial squared. What is the matter with something simple like x+2 or something?

15. ValentinaT

Okay, x + 2

16. Mertsj

17. Mertsj

Use the same variable in both. Lose the v and put x

18. ValentinaT

Could you hold on please, I have to make a short phone call?

19. Mertsj

I'm outta here.