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ValentinaT

Can someone help me create a problem that has a binomial which IS a factor of the polynomial being divided?

  • one year ago
  • one year ago

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  1. Mertsj
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    If 2(3)=6 what is 6/3?

    • one year ago
  2. ValentinaT
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    2.

    • one year ago
  3. Mertsj
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    Is 3 a factor of 6?

    • one year ago
  4. ValentinaT
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    Yes.

    • one year ago
  5. Mertsj
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    So perhaps we could use that idea and apply it to binomials so we end up with a polynomial that has a binomial factor.

    • one year ago
  6. Mertsj
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    Make up a binomial and post it.

    • one year ago
  7. ValentinaT
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    y = 2x + 10

    • one year ago
  8. Mertsj
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    Make up one which is not factorable.

    • one year ago
  9. Mertsj
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    See why you can't get help. I have been trying to help you for more than 2 hours and you have disappeared yet again.

    • one year ago
  10. ValentinaT
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    Sorry, I keep forgetting to check back into Openstudy.

    • one year ago
  11. ValentinaT
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    A non factorable binomial could be \[v^{2} + 16\]

    • one year ago
  12. Mertsj
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    Make up a second binomial

    • one year ago
  13. ValentinaT
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    \[(x - 1)^{2}\]

    • one year ago
  14. Mertsj
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    That is a binomial squared. What is the matter with something simple like x+2 or something?

    • one year ago
  15. ValentinaT
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    Okay, x + 2

    • one year ago
  16. Mertsj
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    Multiply your two binomials.

    • one year ago
  17. Mertsj
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    Use the same variable in both. Lose the v and put x

    • one year ago
  18. ValentinaT
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    Could you hold on please, I have to make a short phone call?

    • one year ago
  19. Mertsj
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    I'm outta here.

    • one year ago
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