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Mertsj Group TitleBest ResponseYou've already chosen the best response.2
dw:1365806403322:dw
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
The only way that can be true is if all factors are positive or 2 are negative and 1 positive.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.0
\[\huge \frac{6}{x+1} > \frac{1}{x}\] \[\huge 6x>x+1\] \[\huge 7x<1\] \[\huge x<\frac{1}{7}\]
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
You can't do that @Azteck You don't know if x is positive or negative thus you don't know whether to flip the inequality symbol or not. The way I showed is the way to handle it.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.0
AH, yeah you're right. I was at a lost there for a moment, but all is well now.
 one year ago
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