Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

MertsjBest ResponseYou've already chosen the best response.2
The only way that can be true is if all factors are positive or 2 are negative and 1 positive.
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
\[\huge \frac{6}{x+1} > \frac{1}{x}\] \[\huge 6x>x+1\] \[\huge 7x<1\] \[\huge x<\frac{1}{7}\]
 one year ago

MertsjBest ResponseYou've already chosen the best response.2
You can't do that @Azteck You don't know if x is positive or negative thus you don't know whether to flip the inequality symbol or not. The way I showed is the way to handle it.
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
AH, yeah you're right. I was at a lost there for a moment, but all is well now.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.