## yashar806 need help !!! one year ago one year ago

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1. yashar806

We have four boxes, each of which contains ten coloured balls: Box 1 contains 4 red balls, 5 green balls and 1 yellow ball Box 2 contains 3 red balls, 5 green balls and 2 yellow balls Box 3 contains 2 red balls, 5 green balls and 3 yellow balls Box 4 contains 1 red ball, 5 green balls and 4 yellow balls If we randomly select one ball from each box, what is the probability of selcecting exactly one red ball? If we randomly select one ball from each box, what is the probability of selcecting at one red ball?

2. honourznr

ı think (4/10)*(3/10)*(2/10)*(1/10)

3. yashar806

4. yashar806

but im not sure how to get that answer

5. honourznr

6. honourznr

we use all box isnt it?

7. yashar806

i guess so

8. yashar806

any ideA?

9. honourznr

ı dont understand question very well 4 balls will red?

10. honourznr

all the balls must be red ? 4 balls ? like red red red red ?

11. electrokid

${4\over4+5+1}\times{3\over3+5+2}\times{2\over2+5+3}\times{1\over1+5+4}=?$

12. yashar806

13. yashar806

of course its add up to 1

14. electrokid

no wait got

15. electrokid

1 ball from EACH box

16. electrokid

so, P = 1red from box1 and 3no-red + 1 red from box2 and 3 no red +...

17. yashar806

still dont get it

18. PeterPan

Okay... what's the probability of getting a red ball from ONLY the first box? That's the product of the probability of getting a red ball from the first box and NOT getting a red ball from the other three boxes...

19. yashar806

should I use bionomial probability?

20. PeterPan

I don't know what that is ^ (c'mon go easy on me :> ) But it seems the odds of getting a red ball from the first box is 2 out of 5 odds of NOT getting a red ball from the second box is 7 out of 10 not getting a red ball from the third : 4 out of 5 not getting a red ball from the fourth : 9 out of 10 Now just multiply these, and this'll be one of the things you add...

21. honourznr

ı did the questions

22. PeterPan

merhaba, @honourznr What did you get? ^.^

23. yashar806

merhaba?

24. honourznr

(4/10*7/10*8/10*9/10)+ (3/10*6/10*8/10*9/10)+(2/10*9/10*7/10*6/10)+(1/10*8/10*7/10*6/10)= 0.436=0.44

25. PeterPan

It's like "hello" only more exotic

26. honourznr

:)

27. honourznr

merhaba

28. PeterPan

Well, as long as @honourznr did the arithmetic correctly... there's no reason for it to be wrong :)

29. PeterPan

On second thought, maybe you need to redo that, @honourznr

30. honourznr

why?

31. PeterPan

Okay, it's correct.. just jumbled up in the products, but correct :D

32. yashar806

woww asweome what about the second one ?

33. PeterPan

At least one red ball?

34. honourznr

for example red green green yellow

35. yashar806

ben turk

36. PeterPan

a little confusing...

37. PeterPan

also, @honourznr I did not understand that :D

38. honourznr

so yashar806 do you understand the answer

39. yashar806

evet

40. honourznr

bileydim en baştan türkçe konuşıurdum:D

41. yashar806

Nerelisiniz?

42. honourznr

sne össye falanmı hazırlnısn

43. yashar806

DogoTürkistan'yi biliyor musun?

44. honourznr

evet biliyorum bnde türkiyedeyim

45. honourznr

46. yashar806

bilmiyorm zatan

47. yashar806

48. honourznr

onur... senin

49. yashar806

50. honourznr

memnun oldum yaşar :) iyiakşamlar ben gidiyorum

51. yashar806

Doğu türkistan'da

52. yashar806

benda qok memnun oldum onur

53. honourznr

bana mesaj yolla konuşuruz sonra ....

54. yashar806

tamam , iyiakshamlar

55. honourznr