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anonymous
 3 years ago
need help !!!
anonymous
 3 years ago
need help !!!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0We have four boxes, each of which contains ten coloured balls: Box 1 contains 4 red balls, 5 green balls and 1 yellow ball Box 2 contains 3 red balls, 5 green balls and 2 yellow balls Box 3 contains 2 red balls, 5 green balls and 3 yellow balls Box 4 contains 1 red ball, 5 green balls and 4 yellow balls If we randomly select one ball from each box, what is the probability of selcecting exactly one red ball? If we randomly select one ball from each box, what is the probability of selcecting at one red ball?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ı think (4/10)*(3/10)*(2/10)*(1/10)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, the answer is 0.44

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but im not sure how to get that answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ı will think wait please

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we use all box isnt it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ı dont understand question very well 4 balls will red?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0all the balls must be red ? 4 balls ? like red red red red ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[{4\over4+5+1}\times{3\over3+5+2}\times{2\over2+5+3}\times{1\over1+5+4}=?\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, the answer is 0.44

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0of course its add up to 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, P = 1red from box1 and 3nored + 1 red from box2 and 3 no red +...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay... what's the probability of getting a red ball from ONLY the first box? That's the product of the probability of getting a red ball from the first box and NOT getting a red ball from the other three boxes...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0should I use bionomial probability?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know what that is ^ (c'mon go easy on me :> ) But it seems the odds of getting a red ball from the first box is 2 out of 5 odds of NOT getting a red ball from the second box is 7 out of 10 not getting a red ball from the third : 4 out of 5 not getting a red ball from the fourth : 9 out of 10 Now just multiply these, and this'll be one of the things you add...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0merhaba, @honourznr What did you get? ^.^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(4/10*7/10*8/10*9/10)+ (3/10*6/10*8/10*9/10)+(2/10*9/10*7/10*6/10)+(1/10*8/10*7/10*6/10)= 0.436=0.44

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's like "hello" only more exotic

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well, as long as @honourznr did the arithmetic correctly... there's no reason for it to be wrong :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0On second thought, maybe you need to redo that, @honourznr

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, it's correct.. just jumbled up in the products, but correct :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0woww asweome what about the second one ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0At least one red ball?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for example red green green yellow

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a little confusing...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0also, @honourznr I did not understand that :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so yashar806 do you understand the answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0bileydim en baştan türkçe konuşıurdum:D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sne össye falanmı hazırlnısn

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0DogoTürkistan'yi biliyor musun?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0evet biliyorum bnde türkiyedeyim

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ancak ben peterpanı anlamadım adam merhaba dedi türk değil nerden anladı türk olduğumu:)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0memnun oldum yaşar :) iyiakşamlar ben gidiyorum

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0benda qok memnun oldum onur

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0bana mesaj yolla konuşuruz sonra ....
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