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yashar806Best ResponseYou've already chosen the best response.1
We have four boxes, each of which contains ten coloured balls: Box 1 contains 4 red balls, 5 green balls and 1 yellow ball Box 2 contains 3 red balls, 5 green balls and 2 yellow balls Box 3 contains 2 red balls, 5 green balls and 3 yellow balls Box 4 contains 1 red ball, 5 green balls and 4 yellow balls If we randomly select one ball from each box, what is the probability of selcecting exactly one red ball? If we randomly select one ball from each box, what is the probability of selcecting at one red ball?
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
ı think (4/10)*(3/10)*(2/10)*(1/10)
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
no, the answer is 0.44
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
but im not sure how to get that answer
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
ı will think wait please
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
we use all box isnt it?
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
ı dont understand question very well 4 balls will red?
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
all the balls must be red ? 4 balls ? like red red red red ?
 one year ago

electrokidBest ResponseYou've already chosen the best response.0
\[{4\over4+5+1}\times{3\over3+5+2}\times{2\over2+5+3}\times{1\over1+5+4}=?\]
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
no, the answer is 0.44
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
of course its add up to 1
 one year ago

electrokidBest ResponseYou've already chosen the best response.0
1 ball from EACH box
 one year ago

electrokidBest ResponseYou've already chosen the best response.0
so, P = 1red from box1 and 3nored + 1 red from box2 and 3 no red +...
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
Okay... what's the probability of getting a red ball from ONLY the first box? That's the product of the probability of getting a red ball from the first box and NOT getting a red ball from the other three boxes...
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
should I use bionomial probability?
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
I don't know what that is ^ (c'mon go easy on me :> ) But it seems the odds of getting a red ball from the first box is 2 out of 5 odds of NOT getting a red ball from the second box is 7 out of 10 not getting a red ball from the third : 4 out of 5 not getting a red ball from the fourth : 9 out of 10 Now just multiply these, and this'll be one of the things you add...
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
merhaba, @honourznr What did you get? ^.^
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
(4/10*7/10*8/10*9/10)+ (3/10*6/10*8/10*9/10)+(2/10*9/10*7/10*6/10)+(1/10*8/10*7/10*6/10)= 0.436=0.44
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
It's like "hello" only more exotic
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
Well, as long as @honourznr did the arithmetic correctly... there's no reason for it to be wrong :)
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
On second thought, maybe you need to redo that, @honourznr
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
Okay, it's correct.. just jumbled up in the products, but correct :D
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
woww asweome what about the second one ?
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
At least one red ball?
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
for example red green green yellow
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
a little confusing...
 one year ago

PeterPanBest ResponseYou've already chosen the best response.1
also, @honourznr I did not understand that :D
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
so yashar806 do you understand the answer
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
bileydim en baştan türkçe konuşıurdum:D
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
sne össye falanmı hazırlnısn
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
DogoTürkistan'yi biliyor musun?
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
evet biliyorum bnde türkiyedeyim
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
ancak ben peterpanı anlamadım adam merhaba dedi türk değil nerden anladı türk olduğumu:)
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
memnun oldum yaşar :) iyiakşamlar ben gidiyorum
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
benda qok memnun oldum onur
 one year ago

honourznrBest ResponseYou've already chosen the best response.2
bana mesaj yolla konuşuruz sonra ....
 one year ago

yashar806Best ResponseYou've already chosen the best response.1
tamam , iyiakshamlar
 one year ago
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