## anonymous 3 years ago need help !!!

• This Question is Open
1. anonymous

We have four boxes, each of which contains ten coloured balls: Box 1 contains 4 red balls, 5 green balls and 1 yellow ball Box 2 contains 3 red balls, 5 green balls and 2 yellow balls Box 3 contains 2 red balls, 5 green balls and 3 yellow balls Box 4 contains 1 red ball, 5 green balls and 4 yellow balls If we randomly select one ball from each box, what is the probability of selcecting exactly one red ball? If we randomly select one ball from each box, what is the probability of selcecting at one red ball?

2. anonymous

ı think (4/10)*(3/10)*(2/10)*(1/10)

3. anonymous

4. anonymous

but im not sure how to get that answer

5. anonymous

6. anonymous

we use all box isnt it?

7. anonymous

i guess so

8. anonymous

any ideA?

9. anonymous

ı dont understand question very well 4 balls will red?

10. anonymous

all the balls must be red ? 4 balls ? like red red red red ?

11. anonymous

${4\over4+5+1}\times{3\over3+5+2}\times{2\over2+5+3}\times{1\over1+5+4}=?$

12. anonymous

13. anonymous

of course its add up to 1

14. anonymous

no wait got

15. anonymous

1 ball from EACH box

16. anonymous

so, P = 1red from box1 and 3no-red + 1 red from box2 and 3 no red +...

17. anonymous

still dont get it

18. anonymous

Okay... what's the probability of getting a red ball from ONLY the first box? That's the product of the probability of getting a red ball from the first box and NOT getting a red ball from the other three boxes...

19. anonymous

should I use bionomial probability?

20. anonymous

I don't know what that is ^ (c'mon go easy on me :> ) But it seems the odds of getting a red ball from the first box is 2 out of 5 odds of NOT getting a red ball from the second box is 7 out of 10 not getting a red ball from the third : 4 out of 5 not getting a red ball from the fourth : 9 out of 10 Now just multiply these, and this'll be one of the things you add...

21. anonymous

ı did the questions

22. anonymous

merhaba, @honourznr What did you get? ^.^

23. anonymous

merhaba?

24. anonymous

(4/10*7/10*8/10*9/10)+ (3/10*6/10*8/10*9/10)+(2/10*9/10*7/10*6/10)+(1/10*8/10*7/10*6/10)= 0.436=0.44

25. anonymous

It's like "hello" only more exotic

26. anonymous

:)

27. anonymous

merhaba

28. anonymous

Well, as long as @honourznr did the arithmetic correctly... there's no reason for it to be wrong :)

29. anonymous

On second thought, maybe you need to redo that, @honourznr

30. anonymous

why?

31. anonymous

Okay, it's correct.. just jumbled up in the products, but correct :D

32. anonymous

woww asweome what about the second one ?

33. anonymous

At least one red ball?

34. anonymous

for example red green green yellow

35. anonymous

ben turk

36. anonymous

a little confusing...

37. anonymous

also, @honourznr I did not understand that :D

38. anonymous

so yashar806 do you understand the answer

39. anonymous

evet

40. anonymous

bileydim en baştan türkçe konuşıurdum:D

41. anonymous

Nerelisiniz?

42. anonymous

sne össye falanmı hazırlnısn

43. anonymous

DogoTürkistan'yi biliyor musun?

44. anonymous

evet biliyorum bnde türkiyedeyim

45. anonymous

46. anonymous

bilmiyorm zatan

47. anonymous

48. anonymous

onur... senin

49. anonymous

50. anonymous

memnun oldum yaşar :) iyiakşamlar ben gidiyorum

51. anonymous

Doğu türkistan'da

52. anonymous

benda qok memnun oldum onur

53. anonymous

bana mesaj yolla konuşuruz sonra ....

54. anonymous

tamam , iyiakshamlar

55. anonymous