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which is a function?

Mathematics
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\[A. \left[ y \right]\]
The guy which has a unique mapping to it.
do you have a better example?

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Other answers:

This may help: http://is.gd/PItqZG
That does help Dean,shy
\[A. x=\left[ y \right]\] \[B. y= \left| x \right|\] \[C. x ^{2} + y ^{2} = 49\] \[D. x = y ^{2}\]
what would be your answer ?
which ever one is a function. . .
which do you think IS a function in the choices you've been provided?
D?
why?
because it has a y. lol im so sorry. im tired!!
hehehe I don't think you read the attachment that was shared to you. read it a little bit, will you? it will help you answer a lot of problems regarding functions
C?
okay, you're just obviously guessing. did you read the attachment?
i did. but none of them look like that. or else i would have known it at first.
so what do you understand about function?
by the way, do you understand the [ ] and | | in A and B respectively?
i understand the absolute value signs but i dont know what the bracket things are
brackets and curly braces are used when there are nested parentheses to avoid confusion –{2x – [3 – (4 – 3x)] + 6x}
so it would be B because the graph of y = |x| passes the vertical line test??
so your A is just simply x = y, which is y = x now if you read the attachment, this could mean f(x) = x
ok so it could mean f(x) = x?
yes, it means that the output is the same as the input f(x) the x inside the parenthesis, gives an output of x f(x) = x f(2) = 2 f(blah) = blah
oh ok. that makes sense now!
thanks! i apologize! Im soo tired!
will it pass the vertical or horizontal line test?
if x = 2 or 3 or 4 etc. it will pass the vertical line test which means it is a function. But it will not pass the horizontal line test which means it is not a 1 - 1 function.
right?
sorry i meant y
x does not pass the vertical line test so it is not a function
input x | output y ------------------ 1 | 1 3 | 3 5 | 5 it is a 1 to 1 no matter what |dw:1365917751738:dw|
>> which is a function? @kaylalynn A function f is the set of ordered pairs (x,y) such that if (x1, y1) AND (x1,y2) are elements of f, then y1 = y2.

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