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ParthKohli
 3 years ago
Factor.
ParthKohli
 3 years ago
Factor.

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ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0I know this simplifies to\[\left(\dfrac{2}{3}x + \dfrac{5}{3}y\right)^3 + \rm blah\]

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0So for the first two terms, should I use \(a^3 + b^3 = (a + b)(a^2  ab + b^2)\)?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0That'd make stuff very long.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2its like \((a+b)^3+(cb)^3(a+c)^3\)

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0Wait, so\[(a + c)(a^2 + 2ab + b^2  (a+b)(c b) + c^2  2cb + b^2)  (a + c)^3\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2\(\large = 3(a+b)(a+c)(bc)\)

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0How did you get that?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0It's correct, but is it some sort of identity taught?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2ok, first take last 2 terms, (cb)^3(a+c)^3 = ... ? use A^3B^3 =...

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2not identity, you need to work that out...

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0\[a^3  b^3 = (a  b)(a^2 + ab + b^2)\]So here,\[= (b +a)(\cdots)\]Err

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2none that i can think of.

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0There's always a shortcut in exam questions. It's not like an Olympiad one.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2then you must be having choices ?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0No choices given. That's all.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2then i'll wait for someone to suggest a shortcut.....

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0OK, thanks for the support :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is Pascal's Triangle any useful? http://www.mathsisfun.com/pascalstriangle.html

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I usually use that, but i don't know if its going to help you?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0@hartnn Oh BTW, I found the solution.

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0http://math.stackexchange.com/questions/361002/factoringalongexpressionintheformab3cb3cb3?noredirect=1#comment775818_361002 Yeah, sort of.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2isn't that exactly what i told you ?
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