## Keandrap15 2 years ago What does 13m2n3p + 21mp2 equal when completely factored? (A)13mp(mn3 + 2p) (B)m2p2(13n3 + 21) (C)mp(13mn3 + 21p) (D)mnp(13mn2 + 21p)

1. AKANicole

i know this one!

2. abb0t

It looks like you can factor out an m and p.

3. AKANicole

let me do it!

4. AKANicole

dude!

5. abb0t

Also. combine all numbers since they are just constants. So multiply 13 x 2 x 3 :)

6. AKANicole

um nvm i dont no this

7. abb0t

Put constants and variables together but keep them separate so you can see

8. AKANicole

idk i think so

9. AKANicole

let meh try

10. abb0t

wait, nevermind, are those 3 and 2's mean they are raised to that power?

11. AKANicole

|dw:1365966144717:dw|

12. AKANicole

sry bad at this i am young ok

13. Keandrap15

abb0t yes the 2 and 3 are raised to the power

14. abb0t

\(13m^2n^3p +21m p^2\) is that correct?

15. abb0t

Ok, simply factor the lowest common factor between them :)

16. Keandrap15

Yes that is correct

17. abb0t

Your two common variables are "m" and "p" That's because you have both of them there. There's no "n" variable on the right side. Now, notice that you have ONE "p" on the left and ONE "m" on the left. Those are your common factors.

18. abb0t

There's also no two common factors between 13 and 21, so you can just leave them in there. In essence, you're taking out ONE "m" and ONE "p" only.

19. abb0t

20. Keandrap15

would it be C?

21. Nurali

correct

22. abb0t

Yep.

23. Keandrap15

thank you