anonymous
  • anonymous
What does 13m2n3p + 21mp2 equal when completely factored? (A)13mp(mn3 + 2p) (B)m2p2(13n3 + 21) (C)mp(13mn3 + 21p) (D)mnp(13mn2 + 21p)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
i know this one!
abb0t
  • abb0t
It looks like you can factor out an m and p.
anonymous
  • anonymous
let me do it!

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More answers

anonymous
  • anonymous
dude!
abb0t
  • abb0t
Also. combine all numbers since they are just constants. So multiply 13 x 2 x 3 :)
anonymous
  • anonymous
um nvm i dont no this
abb0t
  • abb0t
Put constants and variables together but keep them separate so you can see
anonymous
  • anonymous
idk i think so
anonymous
  • anonymous
let meh try
abb0t
  • abb0t
wait, nevermind, are those 3 and 2's mean they are raised to that power?
anonymous
  • anonymous
|dw:1365966144717:dw|
anonymous
  • anonymous
sry bad at this i am young ok
anonymous
  • anonymous
abb0t yes the 2 and 3 are raised to the power
abb0t
  • abb0t
\(13m^2n^3p +21m p^2\) is that correct?
abb0t
  • abb0t
Ok, simply factor the lowest common factor between them :)
anonymous
  • anonymous
Yes that is correct
abb0t
  • abb0t
Your two common variables are "m" and "p" That's because you have both of them there. There's no "n" variable on the right side. Now, notice that you have ONE "p" on the left and ONE "m" on the left. Those are your common factors.
abb0t
  • abb0t
There's also no two common factors between 13 and 21, so you can just leave them in there. In essence, you're taking out ONE "m" and ONE "p" only.
abb0t
  • abb0t
Now, can you make what your answer is?
anonymous
  • anonymous
would it be C?
Nurali
  • Nurali
correct
abb0t
  • abb0t
Yep.
anonymous
  • anonymous
thank you

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