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Keandrap15

  • one year ago

What does 13m2n3p + 21mp2 equal when completely factored? (A)13mp(mn3 + 2p) (B)m2p2(13n3 + 21) (C)mp(13mn3 + 21p) (D)mnp(13mn2 + 21p)

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  1. AKANicole
    • one year ago
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    i know this one!

  2. abb0t
    • one year ago
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    It looks like you can factor out an m and p.

  3. AKANicole
    • one year ago
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    let me do it!

  4. AKANicole
    • one year ago
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    dude!

  5. abb0t
    • one year ago
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    Also. combine all numbers since they are just constants. So multiply 13 x 2 x 3 :)

  6. AKANicole
    • one year ago
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    um nvm i dont no this

  7. abb0t
    • one year ago
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    Put constants and variables together but keep them separate so you can see

  8. AKANicole
    • one year ago
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    idk i think so

  9. AKANicole
    • one year ago
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    let meh try

  10. abb0t
    • one year ago
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    wait, nevermind, are those 3 and 2's mean they are raised to that power?

  11. AKANicole
    • one year ago
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    |dw:1365966144717:dw|

  12. AKANicole
    • one year ago
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    sry bad at this i am young ok

  13. Keandrap15
    • one year ago
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    abb0t yes the 2 and 3 are raised to the power

  14. abb0t
    • one year ago
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    \(13m^2n^3p +21m p^2\) is that correct?

  15. abb0t
    • one year ago
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    Ok, simply factor the lowest common factor between them :)

  16. Keandrap15
    • one year ago
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    Yes that is correct

  17. abb0t
    • one year ago
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    Your two common variables are "m" and "p" That's because you have both of them there. There's no "n" variable on the right side. Now, notice that you have ONE "p" on the left and ONE "m" on the left. Those are your common factors.

  18. abb0t
    • one year ago
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    There's also no two common factors between 13 and 21, so you can just leave them in there. In essence, you're taking out ONE "m" and ONE "p" only.

  19. abb0t
    • one year ago
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    Now, can you make what your answer is?

  20. Keandrap15
    • one year ago
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    would it be C?

  21. Nurali
    • one year ago
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    correct

  22. abb0t
    • one year ago
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    Yep.

  23. Keandrap15
    • one year ago
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    thank you

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