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anonymous
 3 years ago
How do you do this linear system?
{3x+y+2z=3
X2y+3z=1
4x8y+12z=7
anonymous
 3 years ago
How do you do this linear system? {3x+y+2z=3 X2y+3z=1 4x8y+12z=7

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is it matrices or which topic

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0Look at equation 1 where you see the term 1y or just y isolate that y to get 3x+y+2z=3 y=33x2z

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0now go to the other 2 equations and replace y with 33x2z

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let @jim_thompson5910 take care of that

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0so equation 2 goes from x2y+3z=1 to x2(33x2z)+3z=1 x6+6x+4z+3z = 1 7x6+7z = 1 7x+7z = 1+6 7x+7z = 7 7(x+z) = 7 7(x+z)/7 = 7/7 x+z = 1

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0Now focus on Equation 3 4x8y+12z=7 4x8(33x2z)+12z=7 4x24+24x+16z+12z=7 28x24+28z=7 28x+28z=7+24 28x+28z=31

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0After doing all that, things boil down to these 2 equations x+z = 1 28x+28z=31

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0use any method to solve that new system of equations for x and z once you have x and z, you can use them both to find y
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