WAKE UP!!! 1 multiplied by itself is 1
this is what we will yield:
\[y=-3(x^2-2x+1-1)\]
After adding and subtracting 1 within the parentheses, you must now regroup the terms to form a perfect square trinomial. The -1 can be removed from inside the parentheses; however, because of the -3 outside of the parentheses, you must multiply -1 by -3
this is what it would look like:
\[y=-3(x^2-2x+1)-3(-1)\]
-3(-1) = 3
if you are still with me, we just solved the value of k
this confirms one of
@eyad's solution earlier k being 3
next step is to factor what is in the parenthesis
\[(x^2-2x+1) \]
turns into:
\[(x-1)^2\]