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Find the chance that the 5 people have 5 different birthdays.
Here is my workings but I think I have gone wrong somewhere
364/365*364/365*363/365*362/365*361/365= I can't seem to get it right have I calculated something wrong?
 one year ago
 one year ago
Find the chance that the 5 people have 5 different birthdays. Here is my workings but I think I have gone wrong somewhere 364/365*364/365*363/365*362/365*361/365= I can't seem to get it right have I calculated something wrong?
 one year ago
 one year ago

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Jack1Best ResponseYou've already chosen the best response.0
= 1  probability that 2 people have the same birthday
 one year ago

Jack1Best ResponseYou've already chosen the best response.0
sorry, rephrase: = 1[(probability that any 2 people have the same birthday)+(probability that any 3 people have the same birthday)+(probability that any 4 people have the same birthday)+(probability that any 5 people have the same birthday)
 one year ago

whatuBest ResponseYou've already chosen the best response.0
it is a bit like that but I am looking at five people with five different birthdays. I just want to know I am on the right track.
 one year ago

Jack1Best ResponseYou've already chosen the best response.0
not great with probability sorry, will get: @Mertsj @amistre64 @hartnn @Callisto @mathslover these guys are the beez neez
 one year ago

Jack1Best ResponseYou've already chosen the best response.0
maybe they're not on right now, will try: @UnkleRhaukus and @hba pretty please?
 one year ago

Jack1Best ResponseYou've already chosen the best response.0
was thinking now that the answer is 1probability that 5 people have the same birthday...?
 one year ago

whatuBest ResponseYou've already chosen the best response.0
ok think I have worked it i.e. 1 1 person 365 2 364 3 363 4 362 and 5 361 do we mutiple all these with 365 days excluding a leap year? that is five people with five diffrent birthdays
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
my idea is, and it could be faulty ...... \[\binom{5}{5}\left(\frac{1}{365}\right)^{5}\left(\frac{364}{365}\right)^{0}\]
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
ppppp ppppf pppfp ppfpp pfppp fpppp pppff ... i think the count for 5 people is 1+5+10+10+5+1 = 32 different scenarios
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
the probability that any given person has a birthday on a given day is 1/365, so the compliment of that is 364/365
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
...lol, never did like this particular one. satelitte has it tattoed someplace im sure
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
finding the chance that they have the same birthday might be easier; then its just 1same birthdays
 one year ago
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