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whatu
 one year ago
Find the chance that the 5 people have 5 different birthdays.
Here is my workings but I think I have gone wrong somewhere
364/365*364/365*363/365*362/365*361/365= I can't seem to get it right have I calculated something wrong?
whatu
 one year ago
Find the chance that the 5 people have 5 different birthdays. Here is my workings but I think I have gone wrong somewhere 364/365*364/365*363/365*362/365*361/365= I can't seem to get it right have I calculated something wrong?

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Jack1
 one year ago
Best ResponseYou've already chosen the best response.0= 1  probability that 2 people have the same birthday

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0sorry, rephrase: = 1[(probability that any 2 people have the same birthday)+(probability that any 3 people have the same birthday)+(probability that any 4 people have the same birthday)+(probability that any 5 people have the same birthday)

whatu
 one year ago
Best ResponseYou've already chosen the best response.0it is a bit like that but I am looking at five people with five different birthdays. I just want to know I am on the right track.

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0not great with probability sorry, will get: @Mertsj @amistre64 @hartnn @Callisto @mathslover these guys are the beez neez

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0maybe they're not on right now, will try: @UnkleRhaukus and @hba pretty please?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0was thinking now that the answer is 1probability that 5 people have the same birthday...?

whatu
 one year ago
Best ResponseYou've already chosen the best response.0ok think I have worked it i.e. 1 1 person 365 2 364 3 363 4 362 and 5 361 do we mutiple all these with 365 days excluding a leap year? that is five people with five diffrent birthdays

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0my idea is, and it could be faulty ...... \[\binom{5}{5}\left(\frac{1}{365}\right)^{5}\left(\frac{364}{365}\right)^{0}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0ppppp ppppf pppfp ppfpp pfppp fpppp pppff ... i think the count for 5 people is 1+5+10+10+5+1 = 32 different scenarios

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0the probability that any given person has a birthday on a given day is 1/365, so the compliment of that is 364/365

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0...lol, never did like this particular one. satelitte has it tattoed someplace im sure

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0finding the chance that they have the same birthday might be easier; then its just 1same birthdays
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