## pandu Group Title This Problem is worth 1 Point There are six chairs in a row. Person A picks one of the chairs at random. Then Person B picks a chair at random from the five chairs that remain. Find the chance that they pick chairs that are next to each other. one year ago one year ago

1. satellite73

one the chair has been selected, there are 5 chairs left and two next to the first chair chosen, making your answer $$\frac{2}{5}$$

2. gorv

ans will be 1/3 which is correct ... if p1 select 1st chair then p2 will select 2nd chair so probability= 1/6*1/5... now if p1 select any chair between 2 to 5 (probab=1/6)then p2 will have 2 choices either on the left or right(probab=2/5)...and probababilty for ist n last chair will be same so probability=1/6*1/5+1/6*2/5+1/6*2/5+1/6*2/5+1/6*2/5+1/6*1/5=1/3

3. gorv

@satellite73 sry bt ur ans is wrong