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vanndaleyrang
Group Title
Can someone solve this quadratic equation x^2/3x5/3?
 one year ago
 one year ago
vanndaleyrang Group Title
Can someone solve this quadratic equation x^2/3x5/3?
 one year ago
 one year ago

This Question is Open

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
is it \[\frac{x^2}{3}x+\frac{5}{3}=0\]?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.0
holy crap use perenthesis
 one year ago

vanndaleyrang Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 You got it right just change the +5/3 to 5/3
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if so, start by multiplying everything by \(3\) to get \[x^23x5=0\]
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.0
\[1/3\,{x}^{2}x5/3\] that is what maple translates it to
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
unfortunately i don't think this one factors, as a matter of fact i am sure it does not
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
so you have to use the quadratic formula
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.0
so complete the square :) Also i think it is a good idea to say expression=0 when you say solve. Other wise we imply you mean = to 0
 one year ago

vanndaleyrang Group TitleBest ResponseYou've already chosen the best response.0
@timo86m Yeah this is my first time using open study so im trying to my best, lol bare with me. Okay can you show me step by step how to complete the square?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
use \[x=\frac{b\pm\sqrt{b^24ac}}{2a}\] with \(a=1,b=3,c=5\) i would not complete the square for this one
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.0
satallite already started in quadratic formula instead
 one year ago

vanndaleyrang Group TitleBest ResponseYou've already chosen the best response.0
Okay thats fine
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if you want to complete the square, which the quadratic formula does for you in one step, you have to start with \[x^23x=5\] then take half of 3, which is \(\frac{3}{2}\) and write \[(x\frac{3}{2})^2=5+\frac{9}{4}=\frac{27}{4}\] and so \[x\frac{3}{2}=\pm\frac{\sqrt{27}}{2}\] making \[x=\frac{3\pm\sqrt{27}}{2}\]
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.0
altho i am pretty sure you will have to learn completing the square sooner or later :)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
except i made a mistake, \(5+\frac{9}{4}=\frac{29}{4}\)
 one year ago

vanndaleyrang Group TitleBest ResponseYou've already chosen the best response.0
Ok, thank you guys! :) @timo86m @satellite73
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
in any case if the middle term is odd,(3\) is odd, then it is easier to use the quadratic formula
 one year ago
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